Reputation: 23
var a = 0
(... up to var z = 0)
let letterchoosedbyplayer:String = LetterChoosed.text!
"LetterChoosed" is a textbox. The player enter a letter in this textbox. I store the value in the variable "letterchoosedbyplayer". Then i want to check if the variable called 'letterchoosedbyplayer' (it must be a letter of the alphabet) is equal to 1. How can i do that? I want to do that :
if \(letterchoosedbyplayer) = 1 {
}
Last Edit : All my code
let letterchoosedbyplayer:String = LetterChoosed.text!
if Int(letterchoosedbyplayer) == 1 {
print("vous avez perdu")
}
else {
switch letterchoosedbyplayer {
case "a":
print("lettre \(letterchoosedbyplayer) choisie")
a = 1
case "b":
print("lettre \(letterchoosedbyplayer) choisie")
b = 1
default:
print("cas défaut")
}
}
Upvotes: 0
Views: 182
Reputation: 285150
You could include the "1"
case in the switch
statement:
let letterchoosedbyplayer = LetterChoosed.text
if let lettrechoisie = letterchoosedbyplayer where !lettrechoisie.isEmpty {
switch lettrechoisie {
case "1": print("vous avez perdu")
case "a":
print("lettre \(lettrechoisie) choisie")
a = 1
case "b":
print("lettre \(lettrechoisie) choisie")
b = 1
default:
print("cas défaut")
}
}
Note that Int(letterchoosedbyplayer)! == 1
and letterchoosedbyplayer == "1"
is the same thing.
Edit:
For your purpose you might use a dictionary rather than more than 20 single variables
var letterDict : [String : Int] = ["a" : 0, "b" : 0, "c" : 0, ... "z" : 0]
You can set a variable to 1
for example
letterDict["f"] = 1
Then you can check
if let lettrechoisie = letterchoosedbyplayer where !lettrechoisie.isEmpty {
let value = letterDict[lettrechoisie]!
if value == 1 {
// do something
} else {
// do something else
}
}
That avoids also a huge switch
statement.
Upvotes: 0
Reputation: 12839
\()
is used to append any object in a string. I don't think you can use this for your need
Try
if let letterchoosedbyplayer = LetterChoosed.text where letterchoosedbyplayer == "1" {
}
Upvotes: 1