CODEWITHSUNDEEP
objective-cinterface
grey
grey

Reputation: 1150

How do I implement an interface without a default implementation in Objective-C?

I'm coming to Objective-C from ECMAScript like languages, so this is probably the wrong question, but I can't determine how else to ask it:

I have an interface defined in a header file. I don't want to implement it directly, I just want classes to use it.

So say: Car.h is implemented by Telsa.m, Mercedes.m, Peugeot.m, etc.

Is this possible? I have no use for a default implementation of "car", but I want to make sure each of the brands implements the interface so I can pass any "Car" around reliably. I don't want it to be possible to instance a Car.

Thanks in advance for any insight.

Upvotes: 1

Views: 2128

Answers (3)

Amin Negm-Awad
Amin Negm-Awad

Reputation: 16660

To use a protocol for that is a good pattern, because it is very flexible. But looking to your classes Tesla … it seems to be that way, that these are subclasses of a base class Car.

In such cases it might be more convenient for the implementation to make Car a partial abstract base class. That means that Car

  • declares the API as you want
  • partially implements the API
  • is never instantiated

The advantage is that you have to implement methods equal in every subclass in the base class. So it shortens the implementation.

Of course, you can combine that:

@interface Car : NSObject <CarProtocol>
…
@end

@implementation Car
// Define methods that are common for all subclasses of Car
// Define methods included in CarProtocol, but not definable in a base class empty. 
…
@end

@interface Tesla : Car // Protocol is inherited
…
@end

@implementation Tesla
// Override methods that needs a special behavior for this subclass
// Override methods that are not definable at the base class
// Add method definitions that are special to Tesla (i. e. Power plug)
…
@end

@interface AmphibiousCraft : NSObject<CarProtocol, ShipProtocol> // Implementation of Car is no real help
…
@end

@implementation AmphibiousCraft
…
@end

Upvotes: 0

dminones
dminones

Reputation: 2306

In objective-c when you want to write a class you have to specify the class interface (@interface usually in .h file) and the class implmentation (.m file)

When you want to define an interface that any other class can implement in objective-c thats called a protocol.

@protocol XYZPieChartViewDataSource
- (NSUInteger)numberOfSegments;
- (CGFloat)sizeOfSegmentAtIndex:(NSUInteger)segmentIndex;
@optional
- (NSString *)titleForSegmentAtIndex:(NSUInteger)segmentIndex;
- (BOOL)shouldExplodeSegmentAtIndex:(NSUInteger)segmentIndex;
@required
- (UIColor *)colorForSegmentAtIndex:(NSUInteger)segmentIndex;
@end

Therefore you can write a class that implements this protocol, in order to do this first you have to declare that your class implements this protocol (.h file).

@interface MyClass : NSObject <XYZPieChartViewDataSource>
...
@end

After that you have to write the methods that you want to implement, you must write the required ones and you can write if you need to the optional ones

- (BOOL)shouldExplodeSegmentAtIndex:(NSUInteger)segmentIndex {
// do someting
}

- (UIColor *)colorForSegmentAtIndex:(NSUInteger)segmentIndex {
// do someting 
}

As they pointed out you can take a look to the protocol docs: https://developer.apple.com/library/mac/documentation/Cocoa/Conceptual/ProgrammingWithObjectiveC/WorkingwithProtocols/WorkingwithProtocols.html

Upvotes: 2

CRD
CRD

Reputation: 53010

What you are looking for is a protocol, defined in Objective-C using @protocol. These are, perhaps confusingly, the equivalent of Java-style interfaces. You can define a class to implement any number of protocols, and there is no default implementation required. Read Apple's Working with Protocols for the details.

HTH

Upvotes: 5

Related Questions