CODEWITHSUNDEEP
javascriptregex
user2991608
user2991608

Reputation: 55

Regex for 3 3-digit values separated by a period

I'm writing a regex for a software version field which has the following format :

xxx.yyy.zzz

These 3 parts can have between 1 to 3 digits each. Ex :

1.2.3
100.2.300
111.222.333

I formulated this regex for this purpose , but it's incorrect :

[0-9]{1,3}.[0-9]{1,3}.[0-9]{1,3}

What should be modified to get it working correctly ?

Upvotes: 1

Views: 248

Answers (3)

James Monger
James Monger

Reputation: 10665

You need to escape the dots in the regex, otherwise they count as any character.

var regex = /[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}/;
regex.test('1.2.3'); //true
regex.test('100.2.300'); //true
regex.test('111.222.333'); //true

If you don't escape the dots, you will be able to provide any character in the place of the dot.

var badRegex = /[0-9]{1,3}.[0-9]{1,3}.[0-9]{1,3}/;
badRegex.test('1a2z3'); //true
badRegex.test('100-2#300'); //true
badRegex.test('111f2229333'); //true

Upvotes: 3

Tim007
Tim007

Reputation: 2557

Try this

\d{1,3}\.\d{1,3}\.\d{1,3}

or

[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}

Regex demo

Javascript

var re = /\d{1,3}\.\d{1,3}\.\d{1,3}/g;

or

var re = /[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}/g;

Upvotes: 1

Robert
Robert

Reputation: 20286

You should escape dot with \ and also you can use \d which means digit

\d{1,3}\.\d{1,3}\.\d{1,3}

Upvotes: 2

Related Questions