CODEWITHSUNDEEP
shellunixawksed
Gan
Gan

Reputation: 207

How to Split the number into a specific range(between 1000) in unix

For example if the number is 4569. i need the output as 

1 - 1000
1001 - 2000
2001 - 3000
3001 - 4000
4000 - 4569

I wrote the logic in JAVA for this now but I am migrating my code to UNIX. Is there any single liner to split the numbers with specific range?

Upvotes: 0

Views: 717

Answers (3)

Andreas Louv
Andreas Louv

Reputation: 47137

Or POSIX compatible:

#!/bin/sh
max=4569
num=1

while [ "$num" -lt "$max" ]; do
  next=`expr "$num" + "999"`
  [ "$next" -gt "$max" ] && next="$max"
  echo "$num - $next"

  num=`expr "$next" + "1"`
done

Upvotes: 1

jijinp
jijinp

Reputation: 2672

With awk:

awk 'BEGIN{e=999;m=4569;for(i=1;i<=m;i+=1000){k=m-i;if(k<1000){e=k};print i" - "i+e}}'

Upvotes: 2

makadev
makadev

Reputation: 1054

There may be a one-liner with awk. If you have a recent bash you could use bash arithmetics. It's not as fast tho.

sample.sh

#!/bin/bash

(( max = $1 ))
(( num = 0 ))
echo "going for " $max

while (( max >= num )); do
    (( prev = num + 1 ))
    (( num = prev + 999 ))
    if (( num >= max )); then
            echo $prev "-" $max
    else
            echo $prev "-" $num
    fi
done

which prints

$ ./sample.sh 4569
going for  4569
1 - 1000
1001 - 2000
2001 - 3000
3001 - 4000
4001 - 4569

You can modify it accordingly.

Upvotes: 1

Related Questions