CODEWITHSUNDEEP
bashsh
Olivier
Olivier

Reputation: 442

Why my alias does not work with "sh -c"?

I don't understand why, on my server 

php --version

gives me :

PHP 5.6.17

when

sh -c 'php --version'

gives me :

PHP 4.4.9

I just want to execute a command in php 5.6 and not in php 4.4 with "sh -c" command.

In other words, why my php alias does not work with "sh -c" ?

And how to make it work with "sh -c" ?

My .bash_profile :

# .bash_profile

# Get the aliases and functions
if [ -r ${HOME}/.bashrc ] ; then
  source ${HOME}/.bashrc
fi

# User specific environment and startup programs

PATH=$PATH:$HOME/bin
BASH_ENV=$HOME/.bashrc
USERNAME=""

export USERNAME BASH_ENV PATH

My .bashrc :

# .bashrc

# User specific aliases and functions

# Source global definitions
if [ -f /etc/bashrc ]; then
        . /etc/bashrc
fi

alias php='/usr/local/php5.6/bin/php'

Upvotes: 2

Views: 573

Answers (1)

chepner
chepner

Reputation: 531918

Compare the output of bash --version and sh --version.

Your sh is not actually bash, so .bashrc isn't sourced when it starts, so the alias php is not defined in the new shell.

Upvotes: 1

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