CODEWITHSUNDEEP
pythonpython-3.x
Rainy_Daycart
Rainy_Daycart

Reputation: 5

python 3 - math.sqrt - a float is required

I am trying to use a square root as the count for a counted loop, but I keep getting the error "a float is required." I have tried every way that I can think of to convert the value provided by math.sqrt to a float, but I am still getting the message.

Code:

from random import randrange
import math


def getInfo():

    tilesNum = float(input("Please enter number of tiles now: "))



def procedure(tilesNum):

    countX = 0

    SqRoot = float(math.sqrt(tilesNum))

    print(SqRoot)

    for i in range(float(SqRoot)):

        countX = countX + 1
        countY = 0


        for i in range(float(SqRoot)):
            countY = countY + 1
            terrain = randrange(1, 5)

            if terrain == 1:
                print("terrain on tile", countX, countY, "is frozen")

            elif terrain == 2:
                print("terrain on tile", countX, countY, "is flooded")

            elif terrain == 3:
                print("terrain on tile", countX, countY, "is impeded by   rocks")

            else:
                print("terrain on tile", countX, countY, "is overgrown")




def main():

    tilesNum = getInfo()

    procedure(tilesNum)

main()

Error:

Traceback (most recent call last):
  File "C:\Users\Rainy\AppData\Local\Programs\Python\Python35\PBA prototype (problem).py", line 50, in <module>
    main()
  File "C:\Users\Rainy\AppData\Local\Programs\Python\Python35\PBA prototype (problem).py", line 48, in main
    procedure(tilesNum)
  File "C:\Users\Rainy\AppData\Local\Programs\Python\Python35\PBA prototype (problem).py", line 15, in procedure
    SqRoot = float(math.sqrt(tilesNum))
TypeError: a float is required

Any help is greatly appreciated!

Upvotes: 0

Views: 1305

Answers (1)

Robᵩ
Robᵩ

Reputation: 168626

You are missing a return statement. Try this:

def getInfo():
    tilesNum = float(input("Please enter number of tiles now: "))
    return tilesNum

Since your getInfo() has no explicit return statement, it returns None implicitly. Your main() then passes None into procedure(). Inside procedure(), you pass None into math.sqrt(). math.sqrt() complains with a TypeError.

Upvotes: 4

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