CODEWITHSUNDEEP
python
user12398671236
user12398671236

Reputation: 21

String Concatenation and Formatting | Python

word1 = input("Random Name (ex. Ryan):")
word2 = input("Your name (ex. why do you need an example of your name?):")

print("To:", word1, "@gmail.com")
print("From:", word2, "@outlook.com")

Now you almost need to ignore everything except, word 1 and word2 for now.

Im just wondering why is that the output is 

To:name @gmail.com

and not To:[email protected]

Thanks in advance guys!

Upvotes: 1

Views: 64

Answers (2)

zephyr
zephyr

Reputation: 2332

Because in python print automatically adds spaces between the arguments of the print statement, i.e., things separated by commas. If you want to remove that, you can set the sep keyword to a different separator besides a space. Set it to a blank string to have no separator.

>>> print('A','string','with','spaces.')
A string with spaces.
>>> print('A','string','with','no','spaces.', sep = '')
Astringwithnospaces.

Upvotes: 3

Pythonista
Pythonista

Reputation: 11615

You can do 

print("To:" + word1 + "@gmail.com")

Or 

print("To:%[email protected]" % word1)

Or 

print("To:{}@gmail.com".format(word1))

Or as suggested in the comment:

print("To:{0:s}@gmail.com".format(word1))

To print the value the way you want

Doing print(some_val, some_val2, some_val3, ...) will add a space between these values.

Upvotes: 3

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