CODEWITHSUNDEEP
java
herion37
herion37

Reputation: 1

Getting input from example : java calculate 10x20

I want my code to get input from console(not using scanner.in) Example for after compiling, when written java calculate 10x20 it should give 200. My code:

public class Calculate {


public static void main(String[] args) {
        int x= args[0];
        int y= args[1];
int n1 = Integer.parseInt(args[x]);
int n2 = Integer.parseInt(args[y]);
}
return n1*n2;
}

What am I doing wrong here? Thanks.

Upvotes: 0

Views: 162

Answers (3)

Guillaume Barré
Guillaume Barré

Reputation: 4218

What'i wrong here:

args is an array of String so args[0] and args[1]should be Strings

String x= args[0];
String y= args[1];

The correct way to convert a String to int is :

int n1 = Integer.parseInt(x);

The main method has void has return type so in cannot return a value.

Putting all together you should have something like this :

public static void main(String[] args) {
    String x= args[0];
    String y= args[1];
    int n1 = Integer.parseInt(x);
    int n2 = Integer.parseInt(y);
    int result = n1*n2;
    System.out.println(result);
}

To run this code you must call java calculate 10 20 instead of java calculate 10x20

If you really want to run it with java calculate 10x20 you already have a nice answer.

Upvotes: 0

Sabiha
Sabiha

Reputation: 11

The args is a string array . So args[0] and args[1] have to be parsed into int . And you have written return in main which always returns void . Below code works fine .

public class Calculate {

public static void main(String[] args) {
    int x = Integer.parseInt(args[0]);
    int y = Integer.parseInt(args[1]);
    System.out.println(x * y);
}

}

Upvotes: 1

Jo Kachikaran
Jo Kachikaran

Reputation: 582

The way you're passing the input gives you only one argument. 10x20 is a single string argument. To calculate the result you have to do something like this.

public class Calculate {
    public static void main(String[] args) {
        String[] operands = args[0].split("x");
        int n1 = Integer.parseInt(operands[0]);
        int n2 = Integer.parseInt(operands[1]);
        System.out.println(n1*n2);
    }
}

You have to check for valid arguments or you should pass the arguments correctly.

Upvotes: 2

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