How I can count the total of numbers with python if statement?

Question

I want to count the total occurrence of the number 5 in my dataframe df with 4 lists inside it (there are 3 numbers 5 in my df). But in my code bellow the if statement stops when it encounters the first False return and does not count the third 5 in the last list in df. How I can resolve this?

df = [[1,3,5,7,9],[1,2,3,4,5],[2,4,6,8,10],[2,5,6,8,10]]
n,m,counter=0,5,0

for i in range(4):
    if df[n].count(m):
        print('ok')
        counter=counter+1
        n=n+1
    else:
        print('NO')
print(counter)

Answer 1

I approached the problem a bit differently, but here is the code I would use to solve this problem:

df = [[1,3,5,7,9],[1,2,3,4,5],[2,4,6,8,10],[2,5,6,8,10]]

m=5
counter = 0
for sublist in df:
    counter += sublist.count(m)
print(counter)

Rather than creating multiple variables and having a 'for loop', I set up a for loop to iterate through each list in the original list.

Answer 2

You aren't getting to look at every list because you are only incrementing n if you do find a '5' in the list. But you only try 4 times, so you are effectively looking at [2,4,6,8,10] twice and then running out of range.

Answer 3

You need to index with i not with n here:

if df[n].count(m):

Better:

if df[i].count(m):

Shorter way:

sum(x.count(5) for x in df)