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linuxbashshellawk
Reggie Kapros
Reggie Kapros

Reputation: 101

How can I use the cut command in awk?

I would like to use the ls -l file_path|cut -d ' ' -f 1 in awk script.I need the rights of a file and than use it as an index for an array.How can I do that? For example: if the output of the command is this : -rw-rw-r-- Than I would like to be able to do something like this: Array[-rw-rw-r--]++ I tried to do this:

 awk '{ system("ls -l " FILENAME "|cut -d ' ' -f 1") }' `find $1 -type f`

to get the rights but it doesn't work.

Upvotes: 1

Views: 1045

Answers (2)

Ed Morton
Ed Morton

Reputation: 203615

You would not write code like that as it's trying to use awk as a shell. It's like trying to dig a hole using a screwdriver while you're sitting in your backhoe. Instead you would write something like this with GNU tools:

find "$1" -type f -print0 | xargs -0 stat -c %A | awk '{arr[$0]++}'

or even:

find "." -type f -printf '%M\n' | awk '{arr[$0]++}'

Thanks to @CharlesDuffy for bug-fixes and inspiration in the comments.

Upvotes: 2

anubhava
anubhava

Reputation: 785196

Rather than using ls and parsing it's output use stat with getline:

awk '{cmd="stat -c %A " FILENAME; cmd | getline perm; close(cmd); arr[perm]++}'

Upvotes: 1

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