Reputation: 449
So, I have a file that contains a pattern of a string then an int alternating line by line.
Something like this:
John McClane
30
James Bond
150
Indiana Jones
50
In this example, I would set John McClane to a string variable and then 30 to an integer variable. My issue is dealing with two types. I want to use getline()
, but that only works with strings.
Is there an efficient or "right" way of doing this?
Upvotes: 3
Views: 2827
Reputation: 731
You can try like this to read a string then an int alternating line by line.
#include<iostream>
#include<string>
#include<cstdio>
using namespace std;
int main()
{
string name;
int number;
freopen("input.txt", "r", stdin);
while (getline(cin, name))
{
cin >> number;
/*
process the input here
...
...
*/
getline(cin, name); // just to read the new line and/or spaces after the integer
//getchar(); //you can use getchar() instead of getline(cin, name) if there is no spaces after the integer
}
return 0;
}
Thanks !!!
Upvotes: 0
Reputation:
I don't know if this fully works as i didn't tested it however it just compiles fine and answer should be something like this i think.
#include <iostream>
#include <fstream>
#include <string>
#include <cstdlib>
using namespace std;
int main()
{
int counter = 0;
int number;
string test_string;
ifstream myfile ("example.txt");
if (myfile.is_open())
{
while ( getline (myfile,test_string) )
{
cout << test_string << '\n';
++counter;
if(counter % 2 == 0 ){
number = atoi(test_string.c_str());
cout << number << '\n';
}else{
cout << test_string << '\n';
}
}
myfile.close();
}
else cout << "Unable to open file";
return 0;
}
Upvotes: 0
Reputation: 146
One thing about C++ is that there are a large number of ways to accomplish any one task. One way to get integers from strings is to use a stringstream. There is a tutorial on stringstreams here
As for your problem with reading the alternating file, consider the following pseudocode:
boolean isInt = false;
while(fileIsNotOver) {
//getline
if(isInt) {
//use stringstream to get int here
} else {
//do whatever with the name here
}
isInt = !isInt;
}
Upvotes: 0
Reputation: 65
You could make a variable like this
string ibuf;
Then convert it to an integer doing this
getline(cin, ibuf);
(Whatever your int variable is) = strtol(ibuf.c_str(), NULL, 10);
Upvotes: 0
Reputation: 942
There are a number of approaches you could try.
cin >> in;
). If you want a robust program, you can check validity with cin.good()I don't know if there is a "right" way of doing this per say, but it's not a very taxing operation, so whatever you choose should be fine.
Upvotes: 0