CODEWITHSUNDEEP
erlangdata-transferprotocol-buffers
user3531196
user3531196

Reputation:

encoding a record using protobuff

I am looking to encode a record data structure in erlang using protobuff for erlang. I haven't found a function to do so. 

 rd(person, {name = "", phone = [], address}).
 A = #person{phone=[0,8,2,3,4,3,1,2], name="Robert"}.

  protobuffs:encode(1, A, bytes).
  ** exception error: bad argument
  in function  protobuffs:encode_internal/3
    called as protobuffs:encode_internal(1,
                                         #person{
                                          name = "Robert",
                                          phone = [0,8,2,3,4,3,1,2],
                                          address = undefined},
                                         bytes)

   How can I encode a record using protobuff?

This is the module, I am using to encode, https://github.com/basho/erlang_protobuffs

Thank you

Upvotes: 0

Views: 88

Answers (1)

Alexey Romanov
Alexey Romanov

Reputation: 170815

You can't encode arbitrary records you just defined, that's simply not how Protocol Buffers work in any language.

You need to:

  1. Define your message types in a .proto file (read Protocol Buffers documentation for the syntax, supported types, etc.).

  2. Generate code for the desired language(s) from it. In this case, using protobuffs_compile:scan_file(<path-to-your-proto-file>). as shown in the README.

  3. Use the generated code. It will include the person record and encode_person function.

Upvotes: 2

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