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pythonfunctiontypeerroriterablenonetype
Danica Fernandes
Danica Fernandes

Reputation: 103

NoneType Error in Python while using If condition

I am having trouble getting one of my functions in python to work. The code for my function is below:

def checkBlackjack(value, pot, player, wager):
    if (value == 21):
        print("Congratulations!! Blackjack!!")
        pot -= wager
        player += wager
        print ("The pot value is $", pot)
        print ("Your remaining balance is $",player)
        return (pot, player)

The function call is:

potValue, playerBalance = checkBlackjack(playerValue, potValue, playerBalance, wager)

And the error I get is:

potValue, playerBalance = checkBlackjack(playerValue, potValue, playerBalance, wager)
TypeError: 'NoneType' object is not iterable

Since the error talks about not being able to iterate, I am not sure how to relate this to using the if condition.

Any help will really be appreciated. Thanks!

Upvotes: 1

Views: 231

Answers (2)

Terry Jan Reedy
Terry Jan Reedy

Reputation: 19174

Here is an MCVE for this question:

>>> a, b = None
Traceback (most recent call last):
  File "<pyshell#2>", line 1, in <module>
    a, b = None
TypeError: 'NoneType' object is not iterable

At this point, the problem should be clear. If not, one could look up multiple assignment in the manual.

Upvotes: 1

Pythonista
Pythonista

Reputation: 11635

You're only returning something if the condition in your function is met, otherwise the function returns None by default and it is then trying to unpack None into two values (your variables)

Upvotes: 3

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