CODEWITHSUNDEEP
phphtmlmysqlhtml-select
Tim
Tim

Reputation: 69

Using POST to get select option value from HTML form

I have a form where i get some different information. But then i have a Select with multiple options and i want to be able to send this to the database in 1 or 0 / true or false. But it is not working. This is my code so far:

              <select name="multipleSelect[]" multiple>
                <option value="" disabled selected>Choose your option</option>
                <option name="esea" value="esea">ESEA</option>
                <option name="faceit" value="faceit">FaceIT</option>
                <option name="matchmaking" value="matchmaking">Matchmaking</option>
              </select>
              <label>What are you looking to play?</label>

And this is my php:

$esea = 0;
$faceit = 0;
$matchmaking = 0;
foreach ( $_POST['multipleSelect'] as $value ) {
    if ( $value == 'esea' )        { $esea = 1;       }
    if ( $value == 'faceit' )      { $faceit= 1;      }
    if ( $value == 'matchmaking' ) { $matchmaking= 1; }
}   


  // Sätt in dataN
  $sql = "INSERT INTO users ( steamid, profilename, profileurl, avatar, region, age, ranks, esea, faceit, matchmaking, textarea1 ) VALUES ( 
    '{$mysqli->real_escape_string($_POST['steamid'])}', 
    '{$mysqli->real_escape_string($_POST['profilename'])}',
    '{$mysqli->real_escape_string($_POST['profileurl'])}',
    '{$mysqli->real_escape_string($_POST['avatar'])}',
    '{$mysqli->real_escape_string($_POST['region'])}',
    '{$mysqli->real_escape_string($_POST['age'])}',
    '{$mysqli->real_escape_string($_POST['ranks'])}',
    $esea,
    $faceit,
    $matchmaking',
    '{$mysqli->real_escape_string($_POST['textarea1'])}')";
  $insert = $mysqli->query($sql);

I know that this code doesnt work but i don't know what to do to make it work. I wan't to send a 1 or a 0 depending on if the chose the alternative or not.

Upvotes: 0

Views: 2509

Answers (2)

RiggsFolly
RiggsFolly

Reputation: 94642

Your <select> for a multiple selectable dropdown needs to be an array, defined by name="NameThatMakesSense[]"

<select name="NameThatMakesSense[]" multiple>

This will then return you an field called $_POST['NameThatMakesSense'] which itself is an array containing 1 or more values indicating which items in the dropdown were selected. From the value="" attribute of the <option> tag

Then your will need to preprocess the NameThatMakesSense array to pick up which values were actually selected form the multi select dropdown.

$esea = 0;
$esea = 0;
$esea = 0;
foreach ( $_POST['NameThatMakesSense'] as $value ) {
    if ( $value == 'esea' )        { $esea = 1;       }
    if ( $value == 'faceit' )      { $faceit= 1;      }
    if ( $value == 'matchmaking' ) { $matchmaking= 1; }
}    

$sql = "INSERT INTO users 
             ( profilename, profileurl, avatar, region, 
               age, esea, faceit, matchmaking, textarea1 ) 
        VALUES ( 

'{$mysqli->real_escape_string($_POST['profilename'])}',
'{$mysqli->real_escape_string($_POST['profileurl'])}',
'{$mysqli->real_escape_string($_POST['avatar'])}',
'{$mysqli->real_escape_string($_POST['region'])}',
'{$mysqli->real_escape_string($_POST['age'])}',
'{$mysqli->real_escape_string($_POST['ranks'])}',
$esea,
$faceit,
$matchmaking,
'{$mysqli->real_escape_string($_POST['textarea1'])}')";

Upvotes: 1

Pedro Estrada
Pedro Estrada

Reputation: 2404

Your select html tag needs to have a name attribute in order for the form onSubmit to send to the "backend".

like so:

<select name="enterNameThatMakesSense" multiple>  // <----- HERE
  <option value="" disabled selected>Choose your option</option>
  <option name="esea" value="1">ESEA</option>
  <option name="faceit" value="1">FaceIT</option>
  <option name="matchmaking" value="1">Matchmaking</option>
</select>
<label>What are you looking to play?</label>

Upvotes: 2

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