CODEWITHSUNDEEP
stringswiftsubstring
Big Green Alligator
Big Green Alligator

Reputation: 1185

Cannot convert value of type 'Range<Int>' to expected argument type 'Range<Index>' (aka 'Range<String.CharacterView.Index>')

I have a string here, which I am trying to substring.

let desc = "Hello world. Hello World."
var stringRange = 1..<5
desc.substringWithRange(stringRange)

However Swift gives me an error with this. What have I done wrong? I am using the new notation of the stringRange because it doesn't let me use the old one.

Upvotes: 9

Views: 24110

Answers (2)

jrturton
jrturton

Reputation: 119242

The Range you have created does not have the correct type, it is inferred to be an Int. You need to create the range from the string itself:

let desc = "Hello world. Hello World."
let stringRange = desc.startIndex..<desc.startIndex.advancedBy(5)
let sub = desc[stringRange]

It's slightly more complex with String. Alternatively, go back to NSString and NSRange:

let range = NSMakeRange(0, 5)
let sub2 = (desc as NSString).substringWithRange(range)

Upvotes: 10

William Kinaan
William Kinaan

Reputation: 28799

Your 1..<5 is from type Range<Int>, while the method substringWithRange expects a value from type Range<Index>

let desc = "Hello world. Hello World."

var dd = desc.substringWithRange(desc.startIndex..<desc.startIndex.advancedBy(5))

You may apply advanceBy to the desc.startIndex as well

Upvotes: 3

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