CODEWITHSUNDEEP
java
Basic Android
Basic Android

Reputation: 51

double variables implementation and different outputs

I would like to know why there are 2 different outputs from:

double a = 88.0;
System.out.println(a + 10); // 98.0
double result = 88.0;
System.out.println("The result is " + result + 10); // The result is 88.010

Upvotes: 1

Views: 45

Answers (2)

ka98
ka98

Reputation: 7

If you use System.out.println() the items you put inside are automaticly casted into String. The plus is used to add the seperate Strings together.

If you want to do a math operation use the variables inside parenthesises.

So your code shold look like this: 

System.out.println("the result is " + (result + 10));

Upvotes: -2

khelwood
khelwood

Reputation: 59112

When you evaluate "the result is " + result + 10 you are evaluating String + double + int.

When this is executed, the double is first added to the string, creating another string, and then the int is added to that string, giving another string.

So you get:

"the result is " + result + 10
"the result is 88.0" + 10
"the result is 88.010"

This is different from

"the result is " + (result+10)

which would give

"the result is 98.0"

Upvotes: 5

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