CODEWITHSUNDEEP
php
Alê Moraes
Alê Moraes

Reputation: 175

Using double quotes on str_replace

I'm trying to use str_replace to change my code:

$changeli = "li id=\"head{$raiz}\" class=\"head\"";
$changeli2 = "li id=\"foot{$raiz}\" class=\"foot\"";

echo $changeli; // result li id="head-all" class="head"
echo $changeli2; // result li id="foot-all" class="foot"

$footer = str_replace($changeli, $changeli2, $footer );

It doesn't work, but when I remove the text up to the double quotes, it works, as follows:

$changeli = "head{$raiz}";
$changeli2 = "foot{$raiz}";

echo $changeli; // result head-all
echo $changeli2; // result foot-all

$footer = str_replace($changeli, $changeli2, $footer );

Can someone help me?

Upvotes: 3

Views: 181

Answers (3)

ghaziksibi
ghaziksibi

Reputation: 471

try this solution:

$changeli = 'li id="head'.$raiz.'" class="head"';
$changeli2 = 'li id="foot'.$raiz.'" class="foot"';

echo $changeli; // result li id="head-all" class="head"
echo $changeli2; // result li id="foot-all" class="foot"
$footer = '';

$footer = str_replace($changeli, $changeli2, $footer );

Upvotes: 1

ib11
ib11

Reputation: 2558

Better yet, try to use ' instead of " for the outer quote so you don't have to escape it at all. And concatenate $raiz with your string. The problem is most likely characters that should be escaped in html.

Try this, this works (see this code exactly here):

$changeli = 'li id="head'.$raiz.'" class="head"';
$changeli2 = 'li id="foot'.$raiz.'" class="foot"';

// value of $raiz is "-all" at this point (for clarity of code)
echo $changeli; // result should be li id="head-all" class="head"
echo $changeli2; // result should be li id="foot-all" class="foot"

$footer = htmlspecialchars_decode(str_replace(htmlspecialchars($changeli), htmlspecialchars($changeli2), htmlspecialchars($footer)));

Upvotes: 1

David White
David White

Reputation: 1873

Based on what you said the values of $footer and $raiz are, it's hard to see what's going wrong. For example this program:

<?php

$footer = 'id="<li id="head-all" class="head"><p>The news of the...';
$raiz   = '-all';

$changeli  = "li id=\"head{$raiz}\" class=\"head\"";
$changeli2 = "li id=\"foot{$raiz}\" class=\"foot\"";

print "(BEFORE) Footer: $footer\n";
$footer = str_replace($changeli, $changeli2, $footer );
print "(AFTER)  Footer: $footer\n";

produces this output:

(BEFORE) Footer: id="<li id="head-all" class="head"><p>The news of the...
(AFTER)  Footer: id="<li id="foot-all" class="foot"><p>The news of the...

Upvotes: 1

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