Reputation: 385
In my app, i'm sending a file from a client, using sockets. On the other side, another client receive the file using InputStream and then bufferedOutputStream save the file in the system.
I don´t know why, the file isn´t utterly transmited. I think this is because of network overload, anyway, i don´t know how to solve it.
Transmiter is:
Log.d(TAG,"Reading...");
bufferedInputStream.read(byteArrayFile, 0, byteArrayFile.length);
Log.d(TAG, "Sending...");
bufferedOutputStream.write(byteArrayFile,0,byteArrayFile.length);
bufferedOutputStream.flush();
Receiver is:
bufferedOutputStream=new BufferedOutputStream(new FileOutputStream(file));
byteArray=new byte[fileSize];
int currentOffset = 0;
bytesReaded = bufferedInputStream.read(byteArray,0,byteArray.length);
currentOffset=bytesReaded;
do {
bytesReaded = bufferedInputStream.read(byteArray, currentOffset, (byteArray.length-currentOffset));
if(bytesReaded >= 0){ currentOffset += bytesLeidos;
}
} while(bytesReaded > -1 && currentOffset!=fileSize);
bufferedOutputStream.write(byteArray,0,currentOffset);
Upvotes: 1
Views: 1982
Reputation: 310860
You don't state where filesize
came from, but there are numerous problems with this code. Too many to mention. Throw it all away and use DataInputStream.readFully()
. Or use the following copy loop, which doesn't require a buffer the size of the file, a technique which does not scale, assumes that the file size fits into an int
, and adds latency:
byte[] buffer = new byte[8192];
int count;
while ((count = in.read(buffer)) > 0)
{
out.write(buffer, 0, count);
}
Use this at both ends. If you're sending multiple files via the same connection it gets more complex, but you haven't stated that.
Upvotes: 3