CODEWITHSUNDEEP
pythonpython-3.x
IronBat
IronBat

Reputation: 107

Stop Words from python

I have a text file where I am counting the sum of lines, sum of characters and sum of words. How can I clean the data by removing stop words such as (the, for, a) using string.replace()

I have the codes below as of now.

Ex. if the text file contains the line:

"The only words to count are Buttons and Shares for this text"

It should output:

1 Buttons
1 Shares
1 words
1 only
1 text

Although my code does not output the stop words that I have blacklisted but it also removes the stop words if its inside any other words. Below is what my code outputs. 

1 Butns (this is a problem)
1 Shs (this is a problem)
1 words
1 only
1 text

Below is the code I have as of now.

# Open the input file
fname = open('2013_honda_accord.txt', 'r').read()

# COUNT CHARACTERS
num_chars = len(fname)

# COUNT LINES 
num_lines = fname.count('\n')

#COUNT WORDS
fname = fname.lower() # convert the text to lower first

# Remove Stop words 
blacklist = ["the", "to", "are", "and", "for", "this" ]  # Blacklist of words to be filtered out
for word in blacklist:
   fname = fname.replace(word, "")

# Removing special characters from the word count
get_alphabetical_characters = lambda word: "".join([char if char in 'abcdefghijklmnopqrstuvwxyz1234567890-' else '' for char in word])
words = list(map(get_alphabetical_characters, fname.split()))

d = {}
for w in words:
    # if the word is repeated - start count
    if w in d:    
       d[w] += 1
    # if the word is only used once then give it a count of 1
    else:
       d[w] = 1

# Add the sum of all the repeated words 
num_words = sum(d[w] for w in d)

lst = [(d[w], w) for w in d]
# sort the list of words in alpha for the same count 
lst.sort()
# list word count from greatest to lowest (will also show the sort in reserve order Z-A)
lst.reverse()

# output the total number of characters
print('Your input file has characters = ' + str(num_chars))
# output the total number of lines
print('Your input file has num_lines = ' + str(num_lines))
# output the total number of words
print('Your input file has num_words = ' + str(num_words))

print('\n The 30 most frequent words are \n')

# print the number of words as a count from the text file with the sum of each word used within the text
i = 1
for count, word in lst[:10000]:
print('%2s.  %4s %s' % (i, count, word))
i += 1

Thanks

Upvotes: 0

Views: 1299

Answers (3)

James Buerger
James Buerger

Reputation: 204

Move the filtering out of stopwords to when you've created d, the dictionary mapping words to counts. Adding a single line there - if w not in blacklist: - skipping words contained in the blacklist will remove stopwords without changing the other words.

#COUNT WORDS
fname = fname.lower() # convert the text to lower first

# Removing special characters from the word count
get_alphabetical_characters = lambda word: "".join([char if char in 'abcdefghijklmnopqrstuvwxyz1234567890-' else '' for char in word])
words = list(map(get_alphabetical_characters, fname.split()))

# Remove Stop words 
blacklist = ["the", "to", "are", "and", "for", "this" ]  # Blacklist of words to be filtered out

d = {}
for w in words:
  # Do not count words in the blacklist
  if w not in blacklist:
    # if the word is repeated - start count
    if w in d:    
      d[w] += 1
    # if the word is only used once then give it a count of 1
    else:
      d[w] = 1

Upvotes: 0

silent_dev
silent_dev

Reputation: 1616

Assuming that you don't need punctuation for your analysis, you can do something like this -

punctuation_list = ['?',',','.'] # non exhaustive

for punctuation in punctuation_list:
   fname = fname.replace(punctuation, "")

blacklist = ["the", "to", "are", "and", "for", "this" ]  

for word in blacklist:
   fname = fname.replace(" "+word+" ", " ") #replace StopWord preceded by a space and followed by a space with a space

Upvotes: 1

MateoGodlike
MateoGodlike

Reputation: 1

You are removing "to", "are", and replacing them. 

# Remove Stop words 
blacklist = ["the", "to", "are", "and", "for", "this" ]  
# Blacklist of words to be filtered out
for word in blacklist:
   fname = fname.replace(word, "")

Upvotes: 0

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