CODEWITHSUNDEEP
iosswiftswift2uilabel
A Roman
A Roman

Reputation: 19

Assign Text in Code to UILabel! Swift 2.2

Using a tutorial from iOS 8/Swift 1 to create a sample app in an attempt to assign text to a label, using Xcode 7.3/Swift 2.2. Thanks in advance.

import UIKit

class ViewController: UIViewController {

    @IBOutlet var ageCat: UITextField!

    @IBOutlet var resultAge: UILabel!

    @IBAction func findAgeButton(sender: AnyObject) {

        var enteredAge = Int(ageCat.text!)

        var catYears = enteredAge! * 7

        resultAge = "Your cat is \(catYears) in cat years"

    }
}

Upvotes: 1

Views: 359

Answers (3)

A Roman
A Roman

Reputation: 19

Thanks for all the helpful input. This worked for me:

@IBAction func findAgeButton(sender: AnyObject) {

     var catYears = Int(ageCat.text!)!

     catYears = catYears * 7

     resultAge.text = "Your cat is \(catYears) in cat years"

  }

I also added an if/else to address nil entries:

if Int(ageCat.text!) != nil {

    // --insert last 3 lines of code from above here--

  } else {

    resultAge.text = "Please enter a number"

}

Upvotes: 0

Chaudhary Ankit Deshwal
Chaudhary Ankit Deshwal

Reputation: 534

You need to assign value to resultAge.text instead of resultAge:

resultAge.text = "Your cat is \(catYears) in cat years"

Upvotes: -1

Rutger Huijsmans
Rutger Huijsmans

Reputation: 2408

Replace your IBAction func findAgeButton with the following:

@IBAction func findAgeButton(sender: AnyObject) {

// Here the variable is unwrapped. This means the code after it is not executed unless the program is sure that it contains a value.
if let text =  ageCat.text {
    // You can use the unwrapped variable now and won't have to place an exclamation mark behind it to force unwrap it. 
    let enteredAge = Int(text)
     if let age  = enteredAge {
      let catYears = age * 7
      resultAge.text = "Your cat is \(catYears) in cat years"
   }
  }
}

Upvotes: 3

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