Tavian Barnes
Tavian Barnes

Reputation: 12922

Is it okay to define a totally general swap() function?

The following snippet:

#include <memory>
#include <utility>

namespace foo
{
    template <typename T>
    void swap(T& a, T& b)
    {
        T tmp = std::move(a);
        a = std::move(b);
        b = std::move(tmp);
    }

    struct bar { };
}

void baz()
{
    std::unique_ptr<foo::bar> ptr;
    ptr.reset();
}

does not compile for me:

$ g++ -std=c++11 -c foo.cpp
In file included from /usr/include/c++/5.3.0/memory:81:0,
                 from foo.cpp:1:
/usr/include/c++/5.3.0/bits/unique_ptr.h: In instantiation of ‘void std::unique_ptr<_Tp, _Dp>::reset(std::unique_ptr<_Tp, _Dp>::pointer) [with _Tp = foo::bar; _Dp = std::default_delete<foo::bar>; std::unique_ptr<_Tp, _Dp>::pointer = foo::bar*]’:
foo.cpp:20:15:   required from here
/usr/include/c++/5.3.0/bits/unique_ptr.h:342:6: error: call of overloaded ‘swap(foo::bar*&, foo::bar*&)’ is ambiguous
  swap(std::get<0>(_M_t), __p);
      ^
In file included from /usr/include/c++/5.3.0/bits/stl_pair.h:59:0,
                 from /usr/include/c++/5.3.0/bits/stl_algobase.h:64,
                 from /usr/include/c++/5.3.0/memory:62,
                 from foo.cpp:1:
/usr/include/c++/5.3.0/bits/move.h:176:5: note: candidate: void std::swap(_Tp&, _Tp&) [with _Tp = foo::bar*]
     swap(_Tp& __a, _Tp& __b)
     ^
foo.cpp:7:10: note: candidate: void foo::swap(T&, T&) [with T = foo::bar*]
     void swap(T& a, T& b)

Is this my fault for declaring a swap() function so general that it conflicts with std::swap?

If so, is there a way to define foo::swap() so that it doesn't get hauled in by Koenig lookup?

Upvotes: 39

Views: 2309

Answers (3)

user6253369
user6253369

Reputation: 141

The problem is libstdc++'s implementation of unique_ptr. This is from their 4.9.2 branch:

https://gcc.gnu.org/onlinedocs/gcc-4.9.2/libstdc++/api/a01298_source.html#l00339

  338       void
  339       reset(pointer __p = pointer()) noexcept
  340       {
  341     using std::swap;
  342     swap(std::get<0>(_M_t), __p);
  343     if (__p != pointer())
  344       get_deleter()(__p);
  345       }

As you can see, there is an unqualified swap call. Now let's see libcxx (libc++)'s implementation:

https://git.io/vKzhF

_LIBCPP_INLINE_VISIBILITY void reset(pointer __p = pointer()) _NOEXCEPT
{
    pointer __tmp = __ptr_.first();
    __ptr_.first() = __p;
    if (__tmp)
        __ptr_.second()(__tmp);
}

_LIBCPP_INLINE_VISIBILITY void swap(unique_ptr& __u) _NOEXCEPT
    {__ptr_.swap(__u.__ptr_);}

They don't call swap inside reset nor do they use an unqualified swap call.


Dyp's answer provides a pretty solid breakdown on why libstdc++ is conforming but also why your code will break whenever swap is required to be called by the standard library. To quote TemplateRex:

You should have no reason to define such a general swap template in a very specific namespace containing only specific types. Just define a non-template swap overload for foo::bar. Leave general swapping to std::swap, and only provide specific overloads. source

As an example, this won't compile:

std::vector<foo::bar> v;
std::vector<foo::bar>().swap(v);

If you're targeting a platform with an old standard library/GCC (like CentOS), I would recommend using Boost instead of reinventing the wheel to avoid pitfalls like this.

Upvotes: 14

dyp
dyp

Reputation: 39121

  • unique_ptr<T> requires T* to be a NullablePointer [unique.ptr]p3
  • NullablePointer requires lvalues of T* to be Swappable [nullablepointer.requirements]p1
  • Swappable essentially requires using std::swap; swap(x, y); to select an overload for x, y being lvalues of type T* [swappable.requirements]p3

In the last step, your type foo::bar produces an ambiguity and therefore violates the requirements of unique_ptr. libstdc++'s implementation is conforming, although I'd say this is rather surprising.


The wording is of course a bit more convoluted, because it is generic.

[unique.ptr]p3

If the type remove_reference_t<D>::pointer exists, then unique_ptr<T, D>::pointer shall be a synonym for remove_reference_t<D>::pointer. Otherwise unique_ptr<T, D>::pointer shall be a synonym for T*. The type unique_ptr<T, D>::pointer shall satisfy the requirements of NullablePointer.

(emphasis mine)

[nullablepointer.requirements]p1

A NullablePointer type is a pointer-like type that supports null values. A type P meets the requirements of NullablePointer if:

  • [...]
  • lvalues of type P are swappable (17.6.3.2),
  • [...]

[swappable.requirements]p2

An object t is swappable with an object u if and only if:

  • the expressions swap(t, u) and swap(u, t) are valid when evaluated in the context described below, and
  • [...]

[swappable.requirements]p3

The context in which swap(t, u) and swap(u, t) are evaluated shall ensure that a binary non-member function named “swap” is selected via overload resolution on a candidate set that includes:

  • the two swap function templates defined in <utility> and
  • the lookup set produced by argument-dependent lookup.

Note that for a pointer type T*, for purposes of ADL, the associated namespaces and classes are derived from the type T. Hence, foo::bar* has foo as an associated namespace. ADL for swap(x, y) where either x or y is a foo::bar* will therefore find foo::swap.

Upvotes: 25

Tavian Barnes
Tavian Barnes

Reputation: 12922

This technique can be used to avoid foo::swap() getting found by ADL:

namespace foo
{
    namespace adl_barrier
    {
        template <typename T>
        void swap(T& a, T& b)
        {
            T tmp = std::move(a);
            a = std::move(b);
            b = std::move(tmp);
        }
    }

    using namespace adl_barrier;
}

This is how Boost.Range's free-standing begin()/end() functions are defined. I tried something similar before asking the question, but did using adl_barrier::swap; instead, which doesn't work.

As for whether the snippet in the question should work as-is, I'm not sure. One complication I can see is that unique_ptr can have custom pointer types from the Deleter, which should be swapped with the usual using std::swap; swap(a, b); idiom. That idiom is clearly broken for foo::bar* in the question.

Upvotes: 12

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