CODEWITHSUNDEEP
pythoniterator
Mrfuzzy
Mrfuzzy

Reputation: 163

how to call __next__ on iterators n times in python

if we have the following code:

s = "stackoverflow"
si = iter(s)
si.__next__() # Would return s
si.__next__() # Would return t
si.__next__() # Would return a

is there a way without using loops I can get "a" with a single call to __next__(). so basically I want to call __next__() three times and get the third value. (Note that an iterator must be used,I can't just use slicing)

Thank you

Upvotes: 5

Views: 2551

Answers (1)

Ashwini Chaudhary
Ashwini Chaudhary

Reputation: 250881

You can use itertools.islice:

>>> from itertools import islice
>>> si = iter(s)
>>> next(islice(si, 2, 3))
'a'

Upvotes: 10

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