CODEWITHSUNDEEP
androidjsongson
Lê Khánh Vinh
Lê Khánh Vinh

Reputation: 2609

Create a custom GSON Deserialization to map JSON response to object in Android

I'm using GSON library to map JSON response from API and map to an object.

Here is my URL link: 

https://hacker-news.firebaseio.com/v0/item/8863.json?print=pretty

And my model class TopStory

public class TopStory implements Comparable<TopStory> {
    int id;
    String title;
    String by;
    int score;
    List<Integer> kids;
    long time;
    String url;



    public TopStory() {
    }

    public TopStory(int id, String title, String by, int score, long time,String url,List kids) {
        this.id = id;
        this.title = title;
        this.by = by;
        this.score = score;
        this.time = time;
        this.url = url;
        this.kids = kids;
    }

and i'm create a function to create an object from JSON response:

public static TopStory fromJson(JSONObject jsonObject) {
        TopStory topStory = new TopStory();
        Gson gson = new Gson();
        topStory = gson.fromJson(jsonObject.toString(),TopStory.class);

I'm having problem with the field kids. from Response it's an JSONARRAY. how can we deserialize and map to and object field List. And how me exclude to manually Deserialize and assign to specific field?

Upvotes: 0

Views: 255

Answers (3)

Bharatesh
Bharatesh

Reputation: 9009

Actually kids is not a List, it's an Array, so declare kids like this 

Integer[] kids;

Upvotes: 1

Amit Gupta
Amit Gupta

Reputation: 8939

Try using 

Gson gson = new GsonBuilder().create();
TopStory topStory = gson.fromJson(jsonObject.toString(),TopStory.class);

List<Integer> kids;// Correct declaration

Upvotes: 0

yozzy
yozzy

Reputation: 344

You can use Retrofit to make api calls et create a serializable model to get datas.

Upvotes: 0

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