CODEWITHSUNDEEP
javascriptooppropertiesprototype
inthenameofmusik
inthenameofmusik

Reputation: 623

JavaScript Prototypes - Confused

I'm studying prototypes right now and think that I'm almost there but I'm a bit confused on one topic.

Let's say we have:

function Animal(name, gender) {
  this.name = name;
  this.gender = gender;
}

function Cat(species) {
  this.species = species;
}

Cat.prototype.color = null;

Cat.prototype = new Animal();

My question is, why is prototype needed at all for new properties?

Why couldn't we do:

Cat.color = null;

EDIT::

JS Heirarchy map

All the white blocks are from a uml diagram from another SO post. I added the orange boxes to suit this example that I've provided. Does this diagram I've added to still make sense?

My main problem I believe is that I was making the function constructors and the actual prototype objects too similar when in fact they're completely different things. One's a function and one's an object.

EDIT 2

Revised Diagram 2

With this diagram, I'm trying to clarify how the constructor property interacts and what it is exactly connected to, and more specifically, how it affects the use of this. Any comments on the validity would help.

Upvotes: 0

Views: 87

Answers (3)

vtange
vtange

Reputation: 649

"Everything in Javascript is an Object"

Ever wonder why you can use .toString() on say the number 50 without having written Number.toString = function(){....?

Because it's built-into Javascript. All Number.prototypes have the .toString method. And the list goes on for Arrays, Objects, Strings, etc.

Every time you write a Number in JS, imagine (no constructor is really called) calling a Number constructor function similar to your constructor functions for Animal & Cat.

That's what constructor functions do. They create an instance of (theirname).prototype. That's why function Animal() makes something of Animal.prototype and so on.

function Animal() and function Cat() otherwise have nothing to do with Animal.prototype and Cat.prototype. If you actually made a new Animal with new Animal() and then changed the constructor, the new Animal you just made wouldn't be updated, because it was constructed before the constructor changed.

Let's say you make a Cat "Hobbes"

Then after that, when you say Cat.prototype.color = null;, you're saying all objects of Cat.prototype should have a 'null' value for color. This will update Cats you constructed before, since now when you try to find Hobbe's color, it will spit undefined since you didn't give a color to Hobbes himself in function Cat(), but then JS will backtrack to Hobbe's Cat.prototype and find that color is actually null.

Hope that helps.

Upvotes: 1

Redu
Redu

Reputation: 26161

Several things to remind;

  1. A constructor function is used to instantiate new objects. If a constructor function has variables defined with a preceding this. keyword then those will be the properties of the instantiated object. The variables defined with preceding var keyword won't be a part of the instantiated object.
  2. The objects instantiated by a constructor function will have their prototypes assigned to the constructor function's prototype hence they have direct access to the constructor function's prototype. This means they can use (share) the properties and functions within the constructor function's prototype as if they are their own.
  3. The prototype is very useful when you think of instantiating thousands of objects from a constructor function. The unique properties of each object such as name, id, color or whatever should be defined with a preceding this. in the constructor. Such as this.name or this.color however the functionalities that they are expected to share should be defined in the constructors prototype since obviously it would be a waste of memory to reserve a room for them within each instantiated object.

Upvotes: 1

omarjmh
omarjmh

Reputation: 13888

Good question:

Cat.color = null; sets the color only on that one Cat, if you put it on the prototype any 'Cat' you instantiate afterwards will also contain a color property.

Lets say you have something like var tabby = new Cat('feline') with the code above it without the prototype tabby won't have a color.

Upvotes: 2

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