Reputation: 440
I'm working with the Sakila sample database, and trying to get the most viewed film per country. So far I've managed to get the most viewed film of a certain country given its id with the following query:
SELECT
F.title, CO.country, count(F.film_id) as times
FROM
customer C
INNER JOIN
address A ON C.address_id = A.address_id
INNER JOIN
city CI ON A.city_id = CI.city_id
INNER JOIN
country CO ON CI.country_id = CO.country_id
INNER JOIN
rental R ON C.customer_id = R.customer_id
INNER JOIN
inventory I ON R.inventory_id = I.inventory_id
INNER JOIN
film F ON I.film_id = F.film_id
WHERE
CO.country_id = 1
GROUP BY
F.film_id
ORDER BY
times DESC
LIMIT 1;
I supose that I'll have to use this query or something similar in the FORM of another query, but I've tried it all I could think and am completely unable to figure out how to do so.
Thanks in advance!
Upvotes: 1
Views: 71
Reputation: 11796
I admit, this is a hell of a query. But well, as long as it works.
Explanation:
WHERE
and LIMIT
. Resulting in a list of movie-count per countryGROUP_CONCAT(title ORDER BY times DESC SEPARATOR '|||')
, will give ALL titles in that 'row', with the most-viewed title first. The separator doesn't matter, as long as you are sure it will never occurs in a title.SUBSTRING_INDEX('...', '|||', 1)
results in the first part of the string until it finds |||
, in this case the first (and thus most-viewed) titleFull query:
SELECT
country_name,
SUBSTRING_INDEX(
GROUP_CONCAT(title ORDER BY times DESC SEPARATOR '|||'),
'|||', 1
) as title,
MAX(times)
FROM (
SELECT
F.title AS title,
CO.country_id AS country_id,
CO.country AS country_name,
count(F.film_id) as times
FROM customer C INNER JOIN address A ON C.address_id = A.address_id
INNER JOIN city CI ON A.city_id = CI.city_id
INNER JOIN country CO ON CI.country_id = CO.country_id
INNER JOIN rental R ON C.customer_id = R.customer_id
INNER JOIN inventory I ON R.inventory_id = I.inventory_id
INNER JOIN film F ON I.film_id = F.film_id
GROUP BY F.film_id, CO.country_id
) AS count_per_movie_per_country
GROUP BY country_id
Proof of concept (as long as the subquery is correct): SQLFiddle
Upvotes: 2