CODEWITHSUNDEEP
pythonpython-3.xtuples
Cas1337
Cas1337

Reputation: 141

Print elements of a tuple from most inner element

I'm with a python problem, I'm new on this and wanting to know what I'm missing.

The thing I want to do is to print a nested tuple, but from inside to outside.

As an example: ('C', ('B', ('A', ()))) should be printed as null, A, B, C

All tuples maximum size is 2.

I was thinking on using a recursive function in order to do that; I have this code, but I don't know what's wrong.

def tuplePrint(t):
    if len(t) > 1:
        return(tuplePrint(t[1])
    else:
        return t[0]

x = ('E', ('B', ('A', ())))
print(tuplePrint(x))

I'm not asking for the answer for the problem (that would be great), but if only you could tell me what's wrong with the code I'd be grateful.

Anyone? any ideas?

Thanks!

Upvotes: 0

Views: 108

Answers (3)

alykhank
alykhank

Reputation: 453

  1. The return statement on line 3 should not have a ( before the contents of the return.
  2. The base case of your recursion (the else statement, i.e. len(t) <= 1), should return the string "null" or a single-element list ["null"].
  3. The recursive component of your function (return tuplePrint(t[1])) has to also incorporate the current element, so you probably want either tuplePrint(t[1]) + [t[0]] or tuplePrint(t[1]) + " " + t[0].
  4. Once your function returns a string like "null A B E" or a list like [null, A, B, E], you want to print it comma-separated by joining the list: ", ".join(tuplePrint(x)) (in the string case, you should call split() on the string returned by tuplePrint(x).

Resulting in:

def tuplePrint(t):
    if len(t) > 1:
        return tuplePrint(t[1]) + [t[0]]
    else:
        return ["null"]

x = ('E', ('B', ('A', ())))
print(", ".join(tuplePrint(x)))
# null, A, B, E

Upvotes: 1

Sergey Gornostaev
Sergey Gornostaev

Reputation: 7797

def tuple_print(t):
    x, xs = t
    v = 'null'
    if len(xs):
        v = tuple_print(xs)
    return ', '.join((v, x))

Upvotes: 1

co2y
co2y

Reputation: 179

this may work for you

def tuplePrint(t):
    if not t:
        answer.insert(0, "null")
    for each in t:
        if isinstance(each, tuple):
            tuplePrint(each)
        else:
            answer.insert(0, each)

x = ('E', ('B', ('A', ())))
answer = []
tuplePrint(x)
print(answer)

Upvotes: 0

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