CODEWITHSUNDEEP
c++stringc++11vectorfind
Dr. Debasish Jana
Dr. Debasish Jana

Reputation: 7118

GNU g++ 4.9.2 Compilation Error for a find function call

I have StringVec defined as:

typedef std::vector<string> StringVec;

Variable colnames is defined as:

StringVec colnames;

And I have a function as below:

int colIndex(const string &cn) const {
        StringVec::iterator i1;
        i1 = find(colnames.begin(),colnames.end(),cn);
        return(i1 == colnames.end() ? -1 : (i1 - colnames.begin()));
}

When I try to compile with GNU g++ 4.9.2 (C++11), it complains:

error: no matching function for call to 'find(std::vector<std::basic_string<char> >::const_iterator, std::vector<std::basic_string<char> >::const_iterator, const string&)'
 i1 = find(colnames.begin(),colnames.end(),cn);

Even std::find couldn't solve this. Another clue is given by compiler:

note:   template argument deduction/substitution failed:
note:   '__gnu_cxx::__normal_iterator<const std::basic_string<char>*, std::vector<std::basic_string<char> > >' is not derived from 'std::istreambuf_iterator<_CharT>'
  i1 = std::find(colnames.begin(),colnames.end(),cn);

Any clue?

Upvotes: 1

Views: 128

Answers (1)

gsamaras
gsamaras

Reputation: 73366

With the info you gave, I made a minimal example (with the min modifications, did you include the headers?):

#include <string>
#include <algorithm>
#include <vector>

typedef std::vector<std::string> StringVec;
StringVec colnames;
int colIndex(const std::string &cn) {
        StringVec::iterator i1;
        i1 = std::find(colnames.begin(),colnames.end(),cn);
        return(i1 == colnames.end() ? -1 : (i1 - colnames.begin()));
}

int main() {

        return 0;
}

and it compiled just fine with g++ 4.8.4:

gsamaras@gsamaras-A15:~$ g++ -Wall px.cpp 
gsamaras@gsamaras-A15:~$

Upvotes: 3

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