CODEWITHSUNDEEP
pythonlistpython-3.x
User0123456789
User0123456789

Reputation: 758

Printing a list within a list

I am attempting to print a list within a list. I know, I have posted a similar question before - Trouble printing a list within a list, but this is a different issue within the same topic, so please don't flag this as duplicate. I have merged two codes together and this is the final code. In the if statement, I am attempting to print the details of a certain customer of which the user has entered as customer_number. The code searches through myList, which Payments.txt has been appended to. The code can do all of this, but the problem is that it prints this out multiple times; 6 times to be precise:

[['E1234', '12/09/14', '440', 'A', '0']]
Customer number:  E1234
Date of payment:  12/09/14
Payment Amount:  440
Paid Amount:  0

This is my code:

print("Option A: Show a record\nOption Q: Quit")
decision = input("Enter A or Q: ")
myList = []

if decision == "A" or decision == "a":
    myFile = open("Payments.txt")
    customer_number = input("Enter a customer number to view their scores: ")
    record = myFile.readlines()
    for line in record:
        myList.append(line.strip().split(','))
        details = [x for x in myList if x[0] == customer_number]
        if details:
            print(details)
            print("Customer number: ", details[0][0])
            print("Date of payment: ", details[0][1])
            print("Payment Amount: ", details[0][2])
            print("Paid Amount: ", details[0][4])
    myFile.close()
    print(myList)

elif decision == "Q" or "q":
    exit

Upvotes: 2

Views: 270

Answers (1)

kingledion
kingledion

Reputation: 2510

You need to exit the loop when you find and print an answer.

if details:
    print(details)
    print("Customer number: ", details[0][0])
    print("Date of payment: ", details[0][1])
    print("Payment Amount: ", details[0][2])
    print("Paid Amount: ", details[0][4])
    break

Upvotes: 3

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