CODEWITHSUNDEEP
neo4jcypher
Graph Developer J
Graph Developer J

Reputation: 3

neo4j cypher left padding String in Where Clause

I have a String property in my nodes where the length of the String isn't fix. Now i must search the right node by this property but i get a fixed length value from another System. For Example my Node has the Value '0123' but I get the Information '000123' for searching.

I need a function like left padding with Zeros and this in the Where Clause like

MATCH (a:LABEL) where leftPad(a.property, 6, '0') = '000123' return a LIMIT 1

Is something like this possible with a good Performance?

Upvotes: 0

Views: 1000

Answers (2)

cybersam
cybersam

Reputation: 67044

You could do this:

MATCH (a:LABEL)
WHERE SUBSTRING('00000', 0, SIZE(a.property)) + a.property = '000123'
RETURN a
LIMIT 1;

Or, if all the characters are numeric, then you could do this:

MATCH (a:LABEL)
WHERE TOINT(a.property) = TOINT('000123')
RETURN a
LIMIT 1;

However, it would be even better if you could just store the property value as an integer in the first place, and also compare it to an integer, which would be the fastest. This might be very easy to do, depending on your situation.

MATCH (a:LABEL)
WHERE a.property = 000123
RETURN a
LIMIT 1;

Upvotes: 6

stdob--
stdob--

Reputation: 29167

Try it with reduce:

MATCH (a:LABEL) 
WHERE REDUCE(lp='', n in RANGE(0,5-size(a.name)) | lp+'0')+a. a.property = '000123'
RETURN a

or try it with regular expression:

MATCH (a:LABEL)
WHERE a.property =~ '(0){0,3}123'
RETURN a

Upvotes: 0

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