Reputation: 47
I want to use SPARQL to get subjects rdf:value
which have the following resource : http://purl.org/dc/terms/LCSH
<dcterms:subject>
<rdf:Description rdf:nodeID="N4192a7fb1dd6438c94649f7afd192f09">
<rdf:value>United States. Declaration of Independence</rdf:value>
<dcam:memberOf rdf:resource="http://purl.org/dc/terms/LCSH"/>
</rdf:Description>
</dcterms:subject>
<dcterms:subject>
<rdf:Description rdf:nodeID="N887b24b564624253b374ee7c95f0ed51">
<rdf:value>United States -- History -- Revolution, 1775-1783 -- Sources</rdf:value>
<dcam:memberOf rdf:resource="http://purl.org/dc/terms/LCSH"/>
</rdf:Description>
</dcterms:subject>
<dcterms:subject>
<rdf:Description rdf:nodeID="N1b3ed5adb91b4b0c8aa1215180fdfa96">
<rdf:value>JK</rdf:value>
<dcam:memberOf rdf:resource="http://purl.org/dc/terms/LCC"/>
</rdf:Description>
</dcterms:subject>
<dcterms:subject>
<rdf:Description rdf:nodeID="Nc5deb6e74cc6462fbeeb8c1871983f09">
<dcam:memberOf rdf:resource="http://purl.org/dc/terms/LCC"/>
<rdf:value>KF</rdf:value>
</rdf:Description>
</dcterms:subject>
Is there a way to extract the rdf:resource
and use it to filter the subjects?
Upvotes: 0
Views: 1032
Reputation: 85913
The rdf/xml snippet isn't complete, so we can't write a perfect query, but you'll want something like this:
select ?value {
?x dcterms:subject ?subject .
?subject rdf:value ?value .
?subject dcam:memberOf <http://purl.org/dc/terms/LCSH> .
}
If you want to make that a bit shorter, you could do:
select ?value {
?x dcterms:subject [
rdf:value ?value ;
dcam:memberOf <http://purl.org/dc/terms/LCSH> ]
}
And if you really only care about things that have rdf:value properties and are members of LCSH you could skip the first triple altogether:
select ?value {
?x rdf:value ?value ;
dcam:memberOf <http://purl.org/dc/terms/LCSH>
}
Upvotes: 2