CODEWITHSUNDEEP
go
Xys
Xys

Reputation: 10829

undefined: function (declared in another package)

my project organisation looks like this :

main.go looks like this :

package main

import (
  "fmt"
  "cvs/user/project/utils"
)

func main() {
   ...
   utilsDoSomething()
   ...
}

and utils.go :

package utils

import (
  "fmt"
)   

func utilsDoSomething() {
    ...
}

The compiler tells me that :

main.go imported and not used: "cvs/user/project/utils"

main.go undefined: utilsDoSomething

I don't know what I'm doing wrong. Any idea would be helpful, thank you in advance !

Upvotes: 6

Views: 5691

Answers (4)

Cris
Cris

Reputation: 2943

function name also needs to be capitalized in the package utils

func UtilsDoSomething()

Upvotes: 0

Grzegorz Żur
Grzegorz Żur

Reputation: 49181

In Go the symbols (including function names) starting with lower case letters are not exported and so are not visible to other packages.

Rename the function to UtilsDoSomething.

If you strongly oppose exporting this function and you are using Go 1.5 or later, you can make your function visible to only your project by placing utils directory inside internal directory.

Specification of internal packages

Upvotes: 1

Endre Simo
Endre Simo

Reputation: 11551

When you are referencing a function from a package you need to reference it using the package name.Function name (with capital case).

In your case use it as:

utils.UtilsDoSomething().

Upvotes: 1

nemo
nemo

Reputation: 57639

You forgot the package prefix in main.go and your function is not exported, meaning it is not accessible from other packages. To export an identifier, use a capital letter at the beginning of the name:

utils.UtilsDoSomething()

Once you have the utils prefix you can also drop the Utils in the name:

utils.DoSomething()

If you want to import everything from the utils package into the namespace of your main application do:

import . "cvs/user/project/utils"

After that you can use DoSomething directly.

Upvotes: 11

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