CODEWITHSUNDEEP
pythonpython-3.x
Daniel La Cour
Daniel La Cour

Reputation: 57

Using input for date python

I am trying to make a simple code in python 3 that shows you the day when you enter the month year and day. This is the code:

from datetime import date
s = date(2016, 4, 29).weekday()

if s == 0:
    print ("mon")
if s == 1:
    print ("tue")
if s == 2:
    print ("wed")
if s == 3:
    print ("thurs")
if s == 4:
    print ("fri")
if s == 5:
    print ("sat")
if s == 6:
    print ("sun")

The above code works, but I tried to do

from datetime import date
s = date(int(input())).weekday()
if s == 0:
    print ("mon")
if s == 1:
    print ("tue")
if s == 2:
    print ("wed")
if s == 3:
    print ("thurs")
if s == 4:
    print ("fri")
if s == 5:
    print ("sat")
if s == 6:
    print ("sun")

so I could let users enter their own day, but it gives me the following error:

Traceback (most recent call last): 
  File "..\Playground\", line 2, in <module> 
    s = date(int(input())).weekday() 
ValueError: invalid literal for int() with base 10: '2016,'

I used the input 2016, 4, 29 if it helps.

Upvotes: 2

Views: 354

Answers (1)

jDo
jDo

Reputation: 4010

You could do:

from datetime import date

usr_date = [int(x) for x in input().split(",")]
d = date(usr_date[0], usr_date[1], usr_date[2]).weekday()
print (d)

datetime.date() expects 3 integers but input() returns a string. This means that we have to:

  • split the string returned by input() by comma to get three parts
  • convert each part to an integer
  • feed these parts to datetime.date()

This makes more sense, if you ask me:

from datetime import datetime

d = datetime.strptime(input(), '%Y,%m,%d').weekday()
print(d)

datetime.strptime() takes a string as input which is convenient because input() happens to return a string. This means that the splitting and casting/converting isn't necessary. You can find all the different date formats supported by strptime() in the datetime docs.

Upvotes: 2

Related Questions