Reputation: 1153
I have a simple NN model for detecting hand-written digits from a 28x28px image written in python using Keras (Theano backend):
model0 = Sequential()
#number of epochs to train for
nb_epoch = 12
#amount of data each iteration in an epoch sees
batch_size = 128
model0.add(Flatten(input_shape=(1, img_rows, img_cols)))
model0.add(Dense(nb_classes))
model0.add(Activation('softmax'))
model0.compile(loss='categorical_crossentropy',
optimizer='sgd',
metrics=['accuracy'])
model0.fit(X_train, Y_train, batch_size=batch_size, nb_epoch=nb_epoch,
verbose=1, validation_data=(X_test, Y_test))
score = model0.evaluate(X_test, Y_test, verbose=0)
print('Test score:', score[0])
print('Test accuracy:', score[1])
This runs well and I get ~90% accuracy. I then perform the following command to get a summary of my network's structure by doing print(model0.summary())
. This outputs the following:
Layer (type) Output Shape Param # Connected to
=====================================================================
flatten_1 (Flatten) (None, 784) 0 flatten_input_1[0][0]
dense_1 (Dense) (None, 10) 7850 flatten_1[0][0]
activation_1 (None, 10) 0 dense_1[0][0]
======================================================================
Total params: 7850
I don't understand how they get to 7850 total params and what that actually means?
Upvotes: 84
Views: 205618
Reputation: 40526
The number of parameters is 7850 because with every hidden unit you have 784 input weights and one weight of connection with bias. This means that every hidden unit gives you 785 parameters. You have 10 units so it sums up to 7850.
The role of this additional bias term is really important. It significantly increases the capacity of your model. You can read details e.g. here Role of Bias in Neural Networks.
Upvotes: 52
Reputation: 2311
For Dense Layers:
output_size * (input_size + 1) == number_parameters
For Conv Layers:
output_channels * (input_channels * window_size + 1) == number_parameters
Consider following example,
model = Sequential([
Conv2D(32, (3, 3), activation='relu', input_shape=input_shape),
Conv2D(64, (3, 3), activation='relu'),
Conv2D(128, (3, 3), activation='relu'),
Dense(num_classes, activation='softmax')
])
model.summary()
_________________________________________________________________
Layer (type) Output Shape Param #
=================================================================
conv2d_1 (Conv2D) (None, 222, 222, 32) 896
_________________________________________________________________
conv2d_2 (Conv2D) (None, 220, 220, 64) 18496
_________________________________________________________________
conv2d_3 (Conv2D) (None, 218, 218, 128) 73856
_________________________________________________________________
dense_9 (Dense) (None, 218, 218, 10) 1290
=================================================================
Calculating params,
assert 32 * (3 * (3*3) + 1) == 896
assert 64 * (32 * (3*3) + 1) == 18496
assert 128 * (64 * (3*3) + 1) == 73856
assert num_classes * (128 + 1) == 1290
Upvotes: 21
Reputation: 723
Number of parameters is the amount of numbers that can be changed in the model. Mathematically this means number of dimensions of your optimization problem. For you as a programmer, each of this parameters is a floating point number, which typically takes 4 bytes of memory, allowing you to predict the size of this model once saved.
This formula for this number is different for each neural network layer type, but for Dense layer it is simple: each neuron has one bias parameter and one weight per input:
N = n_neurons * ( n_inputs + 1)
.
Upvotes: 3
Reputation:
The easiest way to calculate number of neurons in one layer is: Param value / (number of units * 4)
For example in Paul Lo's answer , number of neurons in one layer is 264710 / (514 * 4 ) = 130
Upvotes: 2
Reputation: 800
I feed a 514 dimensional real-valued input to a Sequential
model in Keras.
My model is constructed in following way :
predictivemodel = Sequential()
predictivemodel.add(Dense(514, input_dim=514, W_regularizer=WeightRegularizer(l1=0.000001,l2=0.000001), init='normal'))
predictivemodel.add(Dense(257, W_regularizer=WeightRegularizer(l1=0.000001,l2=0.000001), init='normal'))
predictivemodel.compile(loss='mean_squared_error', optimizer='adam', metrics=['accuracy'])
When I print model.summary()
I get following result:
Layer (type) Output Shape Param # Connected to
================================================================
dense_1 (Dense) (None, 514) 264710 dense_input_1[0][0]
________________________________________________________________
activation_1 (None, 514) 0 dense_1[0][0]
________________________________________________________________
dense_2 (Dense) (None, 257) 132355 activation_1[0][0]
================================================================
Total params: 397065
________________________________________________________________
For the dense_1 layer , number of params is 264710. This is obtained as : 514 (input values) * 514 (neurons in the first layer) + 514 (bias values)
For dense_2 layer, number of params is 132355. This is obtained as : 514 (input values) * 257 (neurons in the second layer) + 257 (bias values for neurons in the second layer)
Upvotes: 29
Reputation: 2537
The "none" in the shape means it does not have a pre-defined number. For example, it can be the batch size you use during training, and you want to make it flexible by not assigning any value to it so that you can change your batch size. The model will infer the shape from the context of the layers.
To get nodes connected to each layer, you can do the following:
for layer in model.layers:
print(layer.name, layer.inbound_nodes, layer.outbound_nodes)
Upvotes: 9