CODEWITHSUNDEEP
pythonlist
Danny Garcia
Danny Garcia

Reputation: 227

Testing list against list

I know there are other threads with list vs. list, but they don't seem to address my issue. I'm trying to test a series of lists against one specific list and check to see how similar they are. For example,

The "answer key" is as follows: 

answerkey = "B,A,D,D,C,B,D,A,C,C,D,B,A,B,A,C,B,D,A,C,A,A,B,D,D"
lanswerkey = list[answerkey]

and I'm trying to test a series of other lists I am importing, that have the format: 

N00000023,,A,D,D,C,B,D,A,C,C,,C,,B,A,C,B,D,A,C,A,A
N00000024,C,C,D,D,C,B,,A,C,C,D,B,A,B,,C,B,D,A,C,A,B,B,,D

Could I do something like this?:

right = 0
counter3 = 0
for line in f:   
if lanswerkey.split(",")[counter3] == line.split(",")[counter3]:
   right += 4
if lanswerkey.split(",")[counter3] != line.split(",")[counter3]:
   right -= 1
counter3 += 1

Any help would be appreciated!

Upvotes: 0

Views: 82

Answers (3)

xirururu
xirururu

Reputation: 5508

In numpy you can easily compare two arrays with symbol ==, the only problem is you need two arrays with the same length, you can easily deal with this by setting your own rule. In your case, the answerkey has 25 elements and the line1 has just 22 elements, so you can not compare with them, please set a rule by yourself.

import numpy as np

answerkey = "B,A,D,D,C,B,D,A,C,C,D,B,A,B,A,C,B,D,A,C,A,A,B,D,D"
line1  = "N00000023,,A,D,D,C,B,D,A,C,C,,C,,B,A,C,B,D,A,C,A,A"
line2 = "N00000024,C,C,D,D,C,B,,A,C,C,D,B,A,B,,C,B,D,A,C,A,B,B,,D"

# convert your lists to numpy array
answer = np.array(list(answerkey.split(",")))
q1 = np.array(list(line1.split(","))[1:]) # [1:] just to get rid of the "N00000023"
q2 = np.array(list(line2.split(","))[1:])

# print your array length to check whether they are comparable
print len(answer), len(q1), len(q2)
>> 25 22 25

# get your result array
res = answer == q2
>> [False False  True  True  True  True False  True  
   True  True  True  True True  True False  True  True  
   True  True  True  True False  True False True]

# calculate your score
score = sum(res)*4 - (len(res)-sum(res))

print score
>> 70

Upvotes: 2

user5547025
user5547025

Reputation:

If you have

answerkey =           "B,A,D,D,C,B,D,A,C,C,D,B,A,B,A,C,B,D,A,C,A,A,B,D,D"
answer    = "N00000024,B,B,D,D,C,A,D,A,C,D,D,B,A,B,A,C,B,D,A,C,A,A,B,D,D"
# different              ^       ^       ^

you can get the number of different positions like this:

len([x for x in zip(answerkey.split(","), answer.split(",")[1:]) if x[0] != x[1]])
# result 3

Upvotes: 1

alberthkcheng
alberthkcheng

Reputation: 153

Firstly, get a list of answer from answer key.

>>> answerkey = answerkey.split(",")
['B', 'A', 'D', 'D', 'C', 'B', 'D', 'A', 'C', 'C', 'D', 'B', 'A', 'B',
'A', 'C', 'B', 'D', 'A', 'C', 'A', 'A', 'B', 'D', 'D']

Then read the answer:

>>> answer = raw_input().split(",")[1:]
N00000023,,A,D,D,C,B,D,A,C,C,,C,,B,A,C,B,D,A,C,A,A
['', 'A', 'D', 'D', 'C', 'B', 'D', 'A', 'C', 'C', '', 'C', '', 'B', 'A', 'C', 'B', 'D', 'A', 'C', 'A', 'A']

Lastly, compare the answer:

for i in range(len(answerkey)):
  if answerkey[i] == answer[i]:
     right += 4
  else
     right -= 1

If you don't want to use for loop, you may take a look at numpy library which provided the function of element wise comparsion. http://docs.scipy.org/doc/numpy/reference/generated/numpy.equal.html#numpy.equal

Upvotes: 0

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