CODEWITHSUNDEEP
javascriptjqueryregex
Mahesh Verma
Mahesh Verma

Reputation: 69

spilt string with dot but dot not lies in single quote using jquery or regex

I need to split a string like this, on dot. But I don't want to split on dot that are inside of a string (' or "). I'm not parsing a file; just a simple string with no line breaks.

part 1;"12:'[email protected]'.8:'23'.25:'hello'.6:6"

Result should be:

part 1 "12:'[email protected]'"
part 2 "8:'23'"
part 3 "25:'hello'"
part 4 "6:6"

I suppose this can be done with a regex but if not; I'm open to another approach.

EDIT

I have 

str = "12:'[email protected]'.8:'23'.25:'hello'.6:6"

and I expect to get

str[0]=12:[email protected] str[1]=8:'23' 
str[2]=25:'hello' 
str[3]=6:6

but whenever i split it, it shows like that: 

str[0]=12:xyz@gmail
str[1]=com
str[2]=8:'23'
str[3]=25:'hello'
str[4]=6:6

Upvotes: 1

Views: 88

Answers (3)

rock321987
rock321987

Reputation: 11032

I am not sure about split, but you can use replace like this (prone to catastrophic backtracking)

((?:(?:'[^']+')*[^.']*)*)(?:\.|$)

Regex Demo

JS Code

var re = /((?:(?:'[^']+')*[^.']*)*)(?:\.|$)/g; 
var str = '\'1.2\':\'[email protected]\'.8:\'2.3\'.25:\'he.llo\'.6:6\'1.2\''
document.writeln("<pre>" + str.replace(re, "$1\n") + "</pre>");

Upvotes: 2

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626870

You can match with the following regex:

/[^.']+(?:'[^']*')?/g

See the regex demo

Details:

  • [^.']+ - 1 or more characters other than ' and .
  • (?:'[^']*')? - an optional '...' string (' followed with 0+ characters other than ' followed with a '.

Depending on what the content can be, you can use an enhanced version:

/[^.']*(?:'[^']*'[^.']*)*/g

See another demo

Demo 1 (simplified):

var re = /[^.']+(?:'[^']*')?/g; 
var str = '12:\'[email protected]\'.8:\'23\'.25:\'hello\'.6:6';
var m = str.match(re);
document.body.innerHTML = "<pre>" + JSON.stringify(m, 0, 4) + "</pre>";

Demo 2 (if the contents are more complex):

var re = /[^.']*(?:'[^']*'[^.']*)*/g; 
var str = '\'1.2\' 12:\'[email protected]\'.8:\'23\'.25:\'hello\'.6:6';
var res = [];
while ((m = re.exec(str)) !== null) {
    if (m.index === re.lastIndex) {
        re.lastIndex++;
    }
    if (m[0]) { res.push(m[0]);}
}
document.body.innerHTML = "<pre>" + JSON.stringify(res, 0, 4) + "</pre>";

Upvotes: 3

Valery K.
Valery K.

Reputation: 147

Try this regexp:

new RegExp('(\.[^\:]+\:\'?[^\.]+\'?)','g');

Upvotes: 0

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