CODEWITHSUNDEEP
pythonsockets
user6097261
user6097261

Reputation:

Sending 2 message separately using socket

I want to send 2 messages separately using socket. My code so far is below.

Server end:

from socket import *

s = socket(AF_INET, SOCK_STREAM)
s.bind(('localhost', 8888))
s.listen(1)
conn, addr = s.accept()
msg1 = conn.recv(128).decode()
print('msg1', msg1)
msg2 = conn.recv(128).decode()
print('msg2', msg2)

Client end:

from socket import *

sock = socket(AF_INET, SOCK_STREAM)
sock.connect(('localhost', 8888))
msg1 = "hello"
sock.sendall(msg1.encode())
msg2 = "world"
sock.sendall(msg2.encode())

The terminal prints the following:

msg1 helloworld
msg2

What I expected was 2 messages received separately, and for them to be printed like this:

msg1 hello
msg2 world

How can I change my code to get what I want?

Upvotes: 3

Views: 1225

Answers (1)

Wayne Werner
Wayne Werner

Reputation: 51787

You have to either a) only read the amount of information you want to display, or b) block before sending the second message from the client.

A

msg1 = conn.recv(5).decode()
print('msg1', msg1)
msg2 = conn.recv(5).decode()
print('msg2', msg2)

B

(server)

msg1 = conn.recv(128).decode()
print('msg1', msg1)
conn.send(b'Hi')
msg2 = conn.recv(128).decode()
print('msg2', msg2)

(client)

msg1 = "hello"
sock.sendall(msg1.encode())
sock.recv(2048)  # but we don't really care what the message is
msg2 = "world"
sock.sendall(msg2.encode())

Upvotes: 5

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