CODEWITHSUNDEEP
c
user5980704
user5980704

Reputation:

C - Output is rounded

#include <stdio.h>
#include <stdlib.h>

int main() {
  int Sum=0,numbers;
  double Average;
  int counter = 0;

   printf("\nPlease Enter the Numbers one by one\n");
   for(;;) {
     scanf("%d",&numbers);
     if(numbers == 0) {
        break;
     }
     else {
       Sum = Sum + numbers;
       counter++;
     }
   }

   Average = Sum/counter;

   printf("\nSum of the %d Numbers = %d",counter, Sum);
   printf("\nAverage of the %d Numbers = %.4f",counter, Average);

  return 0;
}

I wrote a program which is able to take endless numbers of input add them into one variable and output the average of all the input numbers when the key 0 is pressed.

However, the problem is that when I type in for example 5 and 2 the sum variable has a value of 7. And counter has a value of 2.

However when the mathematical operation starts Average = SUM/Counter, the result is 3.00 not 3.500....

Anyone knows where my problem is?

Would appreciate any help.

Cheers

Marco

Upvotes: 1

Views: 65

Answers (3)

SandBag_1996
SandBag_1996

Reputation: 1601

Average = Sum/counter;

Sum is int.

Average = (double)Sum/counter;

should do it. You need to typecast one of the operands to get the desired result, floating point in this case.

Upvotes: 5

cbo
cbo

Reputation: 96

I don't have the reputation to post comments. So I have to provide it as answer:

dbush's answer is more accurate:

You need to cast one of the operands, not the result.

Would you cast the result, it still were 3.00.

Upvotes: 0

dbush
dbush

Reputation: 224387

Sum and counter are both of type int, so integer division is performed and their result is also of type int.

You need to cast one of the operands to double so that it does floating point division:

Average = (double)Sum/counter;

Upvotes: 3

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