Reputation: 339
Say I have a list, a b c b b d e e f …
, and I don't know how many different kind of elements are in there.
How do I count the number of each unique element and print them out? Output would looks like:
a: 32 b: 12 c: 6 …
Upvotes: 2
Views: 9083
Reputation: 11
It can be easily done using lsearch and llength.
Lets say your list is {a c a c s a a c a} then,
set tempList {a c a c s a a c a}
puts "c : [llength [lsearch -all $tempList c]]"
puts "a : [llength [lsearch -all $tempList a]]"
puts "d : [llength [lsearch -all $tempList d]]"
Output :
c : 3
a : 5
d : 0
Explanation : lsearch -all, will return all the index of matching element and this list of index is returned to llength which will count length of the list.
Upvotes: 1
Reputation: 13252
The dict
or array
solution is the best one and should be preferred. Another way that works on a sorted list of tokens is to match contiguous regions of non-blank tokens.
% regexp -all -inline {(\S+)(?:\s+\1)*} {a a b b b c d d}
{a a} a {b b b} b c c {d d} d
The result is an even-sized list of alternately matched regions of tokens and the token matched in the region. This can be used to print a frequency report for the tokens in the list in list
.
foreach {a b} [regexp -all -inline {(\S+)(?:\s+\1)*} [lsort $list]] {
puts "$b: [llength $a]"
}
Note the limitation that the tokens cannot contain blanks. This can be overcome, but it's simpler to use the array / dict solution which only requires the tokens to be valid list elements.
Documentation: foreach, llength, lsort, puts, Syntax of Tcl regular expressions, regexp
Upvotes: 0
Reputation: 1482
Try this if you have 8.4 or older version of TCL,
set lst "a a a a b b b c c c d d a a a f f f f f s s s s"
set unique [lsort -unique $lst]
foreach f $unique {
set cnt 0
foreach item $lst {
if {$item == $f} {
incr cnt
}
}
puts "$f :: $cnt"
}
Gives Output Like,
% tclsh main.tcl
a :: 7
b :: 3
c :: 3
d :: 2
f :: 5
s :: 4
Upvotes: 1
Reputation: 137567
You have to count them up. This isn't too hard with an array or dictionary of counters. I'll use a dictionary since then they'll be printed in order of first occurrence. (With an array, you'd get a “random” order or you'd have to sort them.)
set counters {}
foreach item $list {
dict incr counters $item
}
dict for {item count} $counters {
puts "${item}: $count"
}
Upvotes: 6