CODEWITHSUNDEEP
java
Dwane Brown Jr
Dwane Brown Jr

Reputation: 55

how do i use substring to eliminate 0's in java

I want my code to take out 0's and put M,B,T ect. after 1,10,or 100, but I don't know how to do it.Basically The program is asking how much money you want like you would put 10000000000. Then kb gets that int, And int b gets length of a, but this is where I have a problem because I can't find a way to make the 10000000000 into 10, and then have it print 'You have $10T', 

public class MinersHavenMoney_Client
{
 private final static String filename = "input.txt";

  public static void main(String[] args) throws FileNotFoundException {
    int x;
    Scanner kb = new Scanner(System.in);
    MinersHavenMoney m1;
    m1 = new MinersHavenMoney();

    System.out.println("How much money do you want");
    int a = kb.nextInt();

    int b = String.valueOf(a).length();

    kb.close();
    if(b<=6)
    System.out.println("You have $" + a);
    else if(b>=7&&b<=9)
    System.out.println("You have $" + c + "M");
    else if(b>9&&b<=12)
    System.out.println("You have $" + a + "B");
    else if(b>12&&b<=15)
    System.out.println("You have $" + a + "T");
   //There is more but there is to much
  }
}

Upvotes: 1

Views: 67

Answers (2)

Elliott Frisch
Elliott Frisch

Reputation: 201447

First you'll need a long to support values into trillions (int has the range -231 to 231-1). Then you could use a regular expression. If the number ends in 12 0s it is trillions, 9 0s it is billions, 6 0s for millions and 3 0s for thousands. Something like,

long b = 10L * 1000 * 1000 * 1000 * 1000;
System.out.println(String.valueOf(b).replaceAll("[0]{12}$", "T")
        .replaceAll("[0]{9}$", "B").replaceAll("[0]{6}$", "M")
        .replaceAll("[0]{3}$", "K"));

Outputs (as requested)

 10T

Upvotes: 2

Peter Lawrey
Peter Lawrey

Reputation: 533520

Instead of comparing the number of digits, you can compare the values.

public static String scale(double value) {
    return value <  1e3 ? asText(value) :
           value <  1e6 ? asText(value / 1e3) + "K" :
           value <  1e9 ? asText(value / 1e6) + "M" :
           value < 1e12 ? asText(value / 1e9) + "B" : 
                          asText(value / 1e12) + "T";
}

public static String asText(double d) {
     return (long) d == d ? Long.toString((long) d) : Double.toString(d);
}

Upvotes: 4

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