Reputation: 1893
I am working on a Gradle script where I need to read the local.properties
file and use the values in the properties file in build.gradle
. I am doing it in the below manner. I ran the below script and it is now throwing an error, but it is also not doing anything like creating, deleting, and copying the file. I tried to print the value of the variable and it is showing the correct value.
Can someone let me know if this is the correct way to do this? I think the other way is to define everything in the gradle.properties
and use it in the build.gradle
. Can someone let me know how could I access the properties in build.gradle
from build.properties
?
build.gradle
file:
apply plugin: 'java'
// Set the group for publishing
group = 'com.true.test'
/**
* Initializing GAVC settings
*/
def buildProperties = new Properties()
file("version.properties").withInputStream {
stream -> buildProperties.load(stream)
}
// If jenkins build, add the jenkins build version to the version. Else add snapshot version to the version.
def env = System.getenv()
if (env["BUILD_NUMBER"]) buildProperties.test+= ".${env["BUILD_NUMBER"]}"
version = buildProperties.test
println "${version}"
// Name is set in the settings.gradle file
group = "com.true.test"
version = buildProperties.test
println "Building ${project.group}:${project.name}:${project.version}"
Properties properties = new Properties()
properties.load(project.file('build.properties').newDataInputStream())
def folderDir = properties.getProperty('build.dir')
def configDir = properties.getProperty('config.dir')
def baseDir = properties.getProperty('base.dir')
def logDir = properties.getProperty('log.dir')
def deployDir = properties.getProperty('deploy.dir')
def testsDir = properties.getProperty('tests.dir')
def packageDir = properties.getProperty('package.dir')
def wrapperDir = properties.getProperty('wrapper.dir')
sourceCompatibility = 1.7
compileJava.options.encoding = 'UTF-8'
repositories {
maven { url "http://arti.oven.c:9000/release" }
}
task swipe(type: Delete) {
println "Delete $projectDir/${folderDir}"
delete "$projectDir/$folderDir"
delete "$projectDir/$logDir"
delete "$projectDir/$deployDir"
delete "$projectDir/$packageDir"
delete "$projectDir/$testsDir"
mkdir("$projectDir/${folderDir}")
mkdir("projectDir/${logDir}")
mkdir("projectDir/${deployDir}")
mkdir("projectDir/${packageDir}")
mkdir("projectDir/${testsDir}")
}
task prepConfigs(type: Copy, overwrite:true, dependsOn: swipe) {
println "The name of ${projectDir}/${folderDir} and ${projectDir}/${configDir}"
from('${projectDir}/${folderDir}')
into('${projectDir}/$configDir}')
include('*.xml')
}
build.properties
file:
# -----------------------------------------------------------------
# General Settings
# -----------------------------------------------------------------
application.name = Admin
project.name = Hello Cool
# -----------------------------------------------------------------
# ant build directories
# -----------------------------------------------------------------
sandbox.dir = ${projectDir}/../..
reno.root.dir=${sandbox.dir}/Reno
ant.dir = ${projectDir}/ant
build.dir = ${ant.dir}/build
log.dir = ${ant.dir}/logs
config.dir = ${ant.dir}/configs
deploy.dir = ${ant.dir}/deploy
static.dir = ${ant.dir}/static
package.dir = ${ant.dir}/package
tests.dir = ${ant.dir}/tests
tests.logs.dir = ${tests.dir}/logs
external.dir = ${sandbox.dir}/FlexCommon/External
external.lib.dir = ${external.dir}/libs
Upvotes: 87
Views: 179695
Reputation: 1560
For Kotlin DSL you can use this
import java.io.FileInputStream
import java.util.Properties
val properties = Properties().apply {
runCatching { load(FileInputStream("local.propertiess")) }
.onFailure { // Optional block if file does not exists
println("Failed to load properties.")
// set default values here
set("gpr.user", "default user name")
}
}
println(properties["gpr.user"]) // During Gradle Sync this will print current value
Advantage of it over other answers is that if local.properties
does not exists then Gradle Sync will not fail, instead it will return empty Properties object. It is also possible to set default values and tell user that the properties file does not exist
Upvotes: 0
Reputation: 24472
This is for Kotlin DSL (build.gradle.kts):
import java.util.*
// ...
val properties = Properties().apply {
load(rootProject.file("my-local.properties").reader())
}
val prop = properties["myPropName"]
In Android projects (when applying the android plugin) you can also do this:
import com.android.build.gradle.internal.cxx.configure.gradleLocalProperties
// ...
val properties = gradleLocalProperties(rootDir)
val prop = properties["propName"]
Upvotes: 7
Reputation: 2227
Just had this issue come up today. We found the following worked both locally and in our pipeline:
In build.gradle:
try {
apply from: 'path/name_of_external_props_file.properties'
} catch (Exception e) {}
This way when an external props file which shouldn't get committed to Git or whatever (as in our case) you are using is not found in the pipeline, this 'apply from:' won't throw an error in it. In our use case we have a file with a userid and password that should not get committed to Git. Aside from the problem of file-reading: we found that the variables we had declared in the external file, maven_user and maven_pass, had in fact to be declared in gradle.properties. That is they simply needed to be mentioned as in:
projectName=Some_project_name
version=1.x.y
maven_user=
maven_pass=
We also found that in the external file we had to put single-quotes around these values too or Gradle got confused. So the external file looked like this:
maven_user='abc123'
maven_pass='fghifh7435bvibry9y99ghhrhg9539y5398'
instead of this:
maven_user=abc123
maven_pass=fghifh7435bvibry9y99ghhrhg9539y5398
That's all we had to do and we were fine. I hope this may help others.
Upvotes: 1
Reputation: 31841
We can use a separate file (config.groovy
in my case) to abstract out all the configuration.
In this example, we're using three environments viz.,
which has properties serverName, serverPort and resources. Here we're expecting that the third property resources may be same in multiple environments and so we've abstracted out that logic and overridden in the specific environment wherever necessary:
config.groovy
resources {
serverName = 'localhost'
serverPort = '8090'
}
environments {
dev {
serverName = 'http://localhost'
serverPort = '8080'
}
test {
serverName = 'http://www.testserver.com'
serverPort = '5211'
resources {
serverName = 'resources.testserver.com'
}
}
prod {
serverName = 'http://www.productionserver.com'
serverPort = '80'
resources {
serverName = 'resources.productionserver.com'
serverPort = '80'
}
}
}
Once the properties file is ready, we can use the following in build.gradle
to load these settings:
build.gradle
loadProperties()
def loadProperties() {
def environment = hasProperty('env') ? env : 'dev'
println "Current Environment: " + environment
def configFile = file('config.groovy')
def config = new ConfigSlurper(environment).parse(configFile.toURL())
project.ext.config = config
}
task printProperties {
println "serverName: $config.serverName"
println "serverPort: $config.serverPort"
println "resources.serverName: $config.resources.serverName"
println "resources.serverPort: $config.resources.serverPort"
}
Let's run these with different set of inputs:
gradle -q printProperties
Current Environment: dev
serverName: http://localhost
serverPort: 8080
resources.serverName: localhost
resources.serverPort: 8090
gradle -q -Penv=dev printProperties
Current Environment: dev
serverName: http://localhost
serverPort: 8080
resources.serverName: localhost
resources.serverPort: 8090
gradle -q -Penv=test printProperties
Current Environment: test
serverName: http://www.testserver.com
serverPort: 5211
resources.serverName: resources.testserver.com
resources.serverPort: 8090
gradle -q -Penv=prod printProperties
Current Environment: prod
serverName: http://www.productionserver.com
serverPort: 80
resources.serverName: resources.productionserver.com
resources.serverPort: 80
Upvotes: 23
Reputation: 368
Another way... in build.gradle:
Add :
classpath 'org.flywaydb:flyway-gradle-plugin:3.1'
And this :
def props = new Properties()
file("src/main/resources/application.properties").withInputStream { props.load(it) }
apply plugin: 'flyway'
flyway {
url = props.getProperty("spring.datasource.url")
user = props.getProperty("spring.datasource.username")
password = props.getProperty("spring.datasource.password")
schemas = ['db_example']
}
Upvotes: 2
Reputation: 12076
If using the default gradle.properties
file, you can access the properties directly from within your build.gradle
file:
gradle.properties
:
applicationName=Admin
projectName=Hello Cool
build.gradle
:
task printProps {
doFirst {
println applicationName
println projectName
}
}
If you need to access a custom file, or access properties which include .
in them (as it appears you need to do), you can do the following in your build.gradle
file:
def props = new Properties()
file("build.properties").withInputStream { props.load(it) }
task printProps {
doFirst {
println props.getProperty("application.name")
println props.getProperty("project.name")
}
}
Take a look at this section of the Gradle documentation for more information.
If you'd like to dynamically set up some of these properties (as mentioned in a comment below), you can create a properties.gradle
file (the name isn't important) and require it in your build.gradle
script.
properties.gradle
:
ext {
subPath = "some/sub/directory"
fullPath = "$projectDir/$subPath"
}
build.gradle
apply from: 'properties.gradle'
// prints the full expanded path
println fullPath
Upvotes: 145