Reputation: 761
Is there a way to check if two expressions are mathematically equal? I expected
tg(x)cos(x) == sin(x)
to output True
, but it outputs False
. Is there a way to make such comparisons with sympy? Another example is
(a+b)**2 == a**2 + 2*a*b + b**2
which surprisingly also outputs False
.
I found some similar questions, but none covered this exact problem.
Upvotes: 39
Views: 21989
Reputation: 718
The solution with simplify was too slow for me (had to crosscheck multiple variables), so I wrote the following function, which does some simple checkes beforehand, to reduce computational time, to use simplify only in the last step.
import numpy as np
import sympy as sp
def check_equal(Expr1,Expr2):
if Expr1==None or Expr2==None:
return(False)
if Expr1.free_symbols!=Expr2.free_symbols:
return(False)
vars = Expr1.free_symbols
your_values=np.random.random(len(vars))
Expr1_num=Expr1
Expr2_num=Expr2
for symbol,number in zip(vars, your_values):
Expr1_num=Expr1_num.subs(symbol, sp.Float(number))
Expr2_num=Expr2_num.subs(symbol, sp.Float(number))
Expr1_num=float(Expr1_num)
Expr2_num=float(Expr2_num)
if not np.allclose(Expr1_num,Expr2_num):
return(False)
if (Expr1.equals(Expr2)):
return(True)
else:
return(False)
Upvotes: 4
Reputation: 968
As previously stated, (expr1 - expr2).simplify()
or expr1.equals(expr2)
will sometimes fail to recognize equality for expressions that are complex to simplify. To deal with this, a numerical evaluation of the expressions with random numbers may constitute a relatively safe "brute force" test. I've adapted the excellent solution by @Okapi575 to:
For example:
Hope it can prove useful:
import sympy as sp
import numpy as np
def check_equal(Expr1, Expr2, n=10, positive=False, strictly_positive=False):
# Determine over what range to generate random numbers
sample_min = -1
sample_max = 1
if positive:
sample_min = 0
sample_max = 1
if strictly_positive:
sample_min = 1
sample_max = 2
# Regroup all free symbols from both expressions
free_symbols = set(Expr1.free_symbols) | set(Expr2.free_symbols)
# Numeric (brute force) equality testing n-times
for i in range(n):
your_values=np.random.uniform(sample_min, sample_max, len(free_symbols))
Expr1_num=Expr1
Expr2_num=Expr2
for symbol,number in zip(free_symbols, your_values):
Expr1_num=Expr1_num.subs(symbol, sp.Float(number))
Expr2_num=Expr2_num.subs(symbol, sp.Float(number))
Expr1_num=float(Expr2_num)
Expr2_num=float(Expr2_num)
if not np.allclose(Expr1_num, Expr2_num):
print("Fails numerical test")
return(False)
# If all goes well so far, check symbolic equality
if (Expr1.equals(Expr2)):
return(True)
else:
print("Passes the numerical test but not the symbolic test")
# Still returns true though
return(True)
EDIT: code updated (1) to compare expressions with differing numbers of free symbols (for example, after symbols got cancelled out during a simplification), and (2) to allow for the specification of a positive or strictly positive random number range.
Upvotes: 1
Reputation: 2709
Check this out from the original sympy themselves.
https://github.com/sympy/sympy/wiki/Faq
Upvotes: 0
Reputation: 712
Alternatively you can use the .equals
method to compare expressions:
from sympy import *
x = symbols('x')
expr1 = tan(x) * cos(x)
expr2 = sin(x)
expr1.equals(expr2)
True
Upvotes: 15
Reputation: 29730
==
represents exact structural equality testing. “Exact” here means that two expressions will compare equal with == only if they are exactly equal structurally. Here, (x+1)^2 and x^2+2x+1 are not the same symbolically. One is the power of an addition of two terms, and the other is the addition of three terms.It turns out that when using SymPy as a library, having
==
test for exact symbolic equality is far more useful than having it represent symbolic equality, or having it test for mathematical equality. However, as a new user, you will probably care more about the latter two. We have already seen an alternative to representing equalities symbolically, Eq. To test if two things are equal, it is best to recall the basic fact that if a=b, then a−b=0. Thus, the best way to check if a=b is to take a−b and simplify it, and see if it goes to 0. We will learn later that the function to do this is calledsimplify
. This method is not infallible—in fact, it can be theoretically proven that it is impossible to determine if two symbolic expressions are identically equal in general—but for most common expressions, it works quite well.
As a demo for your particular question, we can use the subtraction of equivalent expressions and compare to 0 like so
>>> from sympy import simplify
>>> from sympy.abc import x,y
>>> vers1 = (x+y)**2
>>> vers2 = x**2 + 2*x*y + y**2
>>> simplify(vers1-vers2) == 0
True
>>> simplify(vers1+vers2) == 0
False
Upvotes: 35