CODEWITHSUNDEEP
phpsqldatabaseinsert
slickset
slickset

Reputation: 179

Need to figure out total hours between check-in and check-out times

I am trying to create a check-in/check-out table in my database. My check-in form works without issue, inserting the time into my database. The problem occurs when I try to check out. Everything is good on the first entry...

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But when I try to check in and check out again, this happens...

enter image description here

So far so good, but when I check out...

enter image description here Currently, my code updates the out column and totalTime column of all matching child_id's.

Here is my code:

// Select the correct child from the database
$sql_childID = "SELECT id FROM child
                WHERE firstName = '$childFirstName'
                AND lastName = '$childLastName'";
$result = $pdo->query($sql_childID);
$row = $result->fetch();
$var = $row['id'];

// Insert the check out time for the child
$query = "UPDATE checkinout
        SET `out` = :nowTime
        WHERE child_id = $var
        AND `in` IS NOT NULL";
$statement = $pdo->prepare($query);
$statement->bindValue(':nowTime', date("YmjHis"));
$statement->execute();

// Select check in time for specified child
$sql_inTime = "SELECT `in` FROM checkinout
        WHERE child_id = $var";
$inResult = $pdo->query($sql_inTime);
$inRow = $inResult->fetch();
$inTime = strtotime($inRow['in']);

// Select the check out time for specified child
$sql_outTime = "SELECT `out` FROM checkinout
        WHERE child_id = $var";
$outResult = $pdo->query($sql_outTime);
$outRow = $outResult->fetch();
$outTime = strtotime($outRow['out']);

// Find total hours
$totalTime = abs($outTime - $inTime)/(60*60);

// Update totalHours column for specified child
$queryTotalTime = "UPDATE checkinout
                SET totalTime = :totalTime
                WHERE child_id = $var
                AND 'out' IS NOT NULL";
$statement = $pdo->prepare($queryTotalTime);
$statement->bindValue(':totalTime', $totalTime);
$statement->execute();

Upvotes: 3

Views: 1281

Answers (2)

Don't Panic
Don't Panic

Reputation: 41810

I think you could do all of this in your first update statement using TIMESTAMPDIFF rather than figuring the total time with PHP:

UPDATE checkinout
SET 
    out = NOW(),
    totalTime = TIMESTAMPDIFF(SECOND, `in`, NOW()) / 3600
WHERE
    child_id = $var
    AND out IS NULL

The criteria WHERE out IS NULL will only update rows that do not have a value in the out column yet.

Upvotes: 3

nazmul19
nazmul19

Reputation: 32

IF you have MySQL Db THEN sql will be

SELECT TIMESTAMPDIFF(HOUR,in,out) from checkinout;

Upvotes: 1

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