Reputation: 28125
I need to parse some CSS code like:
color: black;
font-family:"Courier New";
background:url('test.png');
color: red;
--crap;
Into:
array (
'color'=>'red',
'font-family'=>'"Courier New"',
'background'=>'url(\'test.png\')',
'--crap'=>''
)
{...}
) or selectors ( a.myclass#myid
).color:red;
) completely override the original items ( color:black;
).Upvotes: 2
Views: 1844
Reputation: 454922
You can try:
$result = array();
if(preg_match_all('/\s*([-\w]+)\s*:?\s*(.*?)\s*;/m',$input,$m))
var_dump($m);
// $m[1] contains all the properties
// $m[2] contains their respective values.
for($i=0;$i<count($m[1]);$i++) {
$result[$m[1][$i]] = $m[2][$i];
}
}
Upvotes: 0
Reputation: 57258
I found this few weeks back and looks interesting.
Example:
$Parser = new cssparser();
$Results = $Parser->ParseStr("color: black;font-family:"CourierNew";background:url('test.png');color: red;--crap;");
Upvotes: 0
Reputation: 48284
Here's a simple version:
$a = array();
preg_match_all('/^\s*([^:]+)(:\s*(.+))?;\s*$/m', $css, $matches, PREG_SET_ORDER);
foreach ($matches as $match)
$a[$match[1]] = isset($match[3]) ? $match[3] : null;
Sample output:
array(4) {
["color"]=>
string(3) "red"
["font-family"]=>
string(13) ""Courier New""
["background"]=>
string(15) "url('test.png')"
["--crap"]=>
NULL
}
Not tested with anything except your source data, so I'm sure it has flaws. Might be enough to get you started.
Upvotes: 2