Reputation: 165
I need to remove every line that has value like SUPMA
in the 4th column.
My data looks like this:
abc;def;ghi;SUPMA;klm
abc;def;ghi;SUPMA;klm
SUPMA;def;ghi;MA;klm
abc;def;ghi;SUPMA;klm
abc;def;ghi;SUP;klm
In this example, I want to keep the 3th and 5th lines.
How can i do this in bash script? Can i use AWK?
Thanks
Upvotes: 1
Views: 86
Reputation: 50019
awk -F";" '$4!="SUPMA"' yourfile.txt
Here awk splits the records by semicolon, then tests the 4th position for SUPMA
. By default, if that condition passes, it will print the line.
Upvotes: 2
Reputation: 1517
awk -F\; '$4 !~/SUPMA/' file
SUPMA;def;ghi;MA;klm
abc;def;ghi;SUP;klm
Upvotes: 1