CODEWITHSUNDEEP
phpwordpresscurl
user3025605
user3025605

Reputation: 323

php curl returning blank data if used inside function

I'm new to php. I'm trying to write a simple plugin that calls the api and returns a JSON response.

When I write the same code outside function, I get a JSON response. But the issue is when I use the function below, it doesn't return any value.. The page seems blank

Here is my function

function getDOTD(){
try{        
    $curl = curl_init();
    curl_setopt($curl, CURLOPT_URL, $baseUrl."offers/v1/dotd/json");
    curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($curl, CURLOPT_FOLLOWLOCATION, 1);
    curl_setopt($curl, CURLOPT_HTTPHEADER, array('Fk-Affiliate-Id:'.get_option('affiliate_id'),'Fk-Affiliate-Token:'.get_option('affiliate_token')));       
    $result = curl_exec($curl);
    curl_close($curl);
    print($result);

} catch (Exception $e) {
    echo 'Caught exception: ',  $e->getMessage(), "\n"; abort;
}
}

i have also tried to use return instead of print() but that too didn't worked. this is how i call my function - 

print(getDOTD());

Any help appreciated... TIA :)

Upvotes: 0

Views: 286

Answers (1)

Enrique Chavez
Enrique Chavez

Reputation: 1429

You need to know how the variables scope works.

From the PHP Documentation

<?php
$a = 1; /* global scope */
function test(){
    echo 'local variable: ' . $a; /* reference to local scope variable // NULL */
}
test();
?>

To be able to access to the global scope you need to use the global keyword inside your function

<?php
$a = 'Hello World'; /* global scope */
function test(){
    global $a;
    echo 'global variable: ' . $a; /* reference to global scope variable // Hello World */
}
test();
?>

More info about the variables scope

Upvotes: 1

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