CODEWITHSUNDEEP
arraysassemblyx86multiplication
user6128930
user6128930

Reputation: 19

The product of elements of the odd positions assembly

i have question , i hope you can help me to find the right solution

I wrote this code to calculate the addition of odd numbers in array using assembly x8086 .

I want now to calculate the multiplication of the elements of the odd POSITION

For example :
x DB 1,3,3,4,5,7 n DB 6 The product is: 84 (produit de x [1], x [3], x [5])

Thank you 

include 'emu8086.inc '   
org 100h  
LEA SI, array  
MOV AX,0  
MOV CX,0
MOV BX,1


for: 
CMP CX,n 
JGE endfor  
CMP CX,BX 
JNE else  

ADD AX,[SI]    
ADD CX,1
ADD BX,2
ADD SI,2


JMP endif 
else: 
ADD CX,1
ADD SI,2
endif:


JMP for
ENDFOR:



 call PRINT_NUM   
 ret 

  array dw 1,9,3,4,5,8,2
  n dw 7

  DEFINE_PRINT_NUM
  DEFINE_PRINT_NUM_UNS
  END

Upvotes: 1

Views: 208

Answers (1)

Fifoernik
Fifoernik

Reputation: 9899

You need to change only 2 instructions in your program:

  • Change ADD AX,[SI] into mul word ptr [si]. This leaves the product in DX:AX but since the numbers involved are so small the DX register will remain zero.
  • Initialize the AX register with 1 instead of 0, else the product would always be zero! At the 4th line of this program change MOV AX,0 into mov ax,1.

You could improve the program by moving the following lines below the "endif" label. They get executed in any case:

ADD CX,1
ADD SI,2

Upvotes: 1

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