CODEWITHSUNDEEP
iosenumsswift2
Leem.fin
Leem.fin

Reputation: 42692

can not pass Enum type as parameter type of function

I am new in iOS Swift 2.

I have defined a simple function:

// ERROR: 'Method' is ambiguous for type lookup in this context
func sendRequest(method: Method, resource: String) -> NSDictionary {
     Alamofire.request(method, "https://httpbin.org/get")
}

As you see, I defined the first parameter has type Method, which is used by Alamofire. I looked into the Method, it is a Enum defined as below:

public enum Method: String {
    case OPTIONS, GET, HEAD, POST, PUT, PATCH, DELETE, TRACE, CONNECT
}

Why I can not use enum type as parameter type of my function?

(The reason why I want to do this is I don't want to pass String type and check if String is e.g. 'get' then use .GET, so, I want to directly pass the Method enum value to the function.)

==== update ====

Method is from Alamofire library, I can't change anything. Looks like it is a name conflicts. But how to get rid of this problem?

Upvotes: 0

Views: 245

Answers (2)

dan
dan

Reputation: 9825

There compiler sees more than one type named Method (Alamofire.Method and ObjectiveC.Method) and doesn't know which one you want to use for your function.

You have to prefix the type name with the module name to tell it which one to use:

func sendRequest(method: Alamofire.Method, resource: String) -> NSDictionary {
     Alamofire.request(method, "https://httpbin.org/get")
}

Upvotes: 1

Rob Napier
Rob Napier

Reputation: 299663

Method is ambiguous with the runtime type of the same name. I recommend selecting a different type name that does not collide with existing types.

Upvotes: 0

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