Reputation: 133
I wanted a text field to take only numbers as some control keys and number should be exactly four digit long. My code is as Follows:
<div id="main" role="main">
Input a 4-digit: <input type="text" class="validateYearTextBox" />
</div>
<div id="alert"></div>
function checkValidInput() {
$(".validateYearTextBox").keydown(function(event) {
if (!((event.keyCode == 46 ||
event.keyCode == 8 ||
event.keyCode == 37 ||
event.keyCode == 39 ||
event.keyCode == 9) ||
$(this).val().length < 4 &&
((event.keyCode >= 48 && event.keyCode <= 57) ||
(event.keyCode >= 96 && event.keyCode <= 105)))) {
// Stop the event
event.preventDefault();
return false;
}
});
}
$(document).ready(function() {
checkValidInput();
});
when I enter a 4 digit in the text box a alert should be appear in div as "valid"
this is the Fiddle
Upvotes: 0
Views: 49
Reputation: 3
Try this simple script after adding onblur="checkValidInput" id="validateYearTextBox" to input tag
function checkValidInput(){
var x,text;
x=document.getelementbyid("validateYearTextBox").value;
if(x==4)
text="Valid";
else
text="Not valid";
}
document.getelementbyid("alert").innerHTML=text;
Upvotes: 0
Reputation: 2482
Try following:
<div id="main" role="main">
Input a 4-digit: <input type="text" class="validateYearTextBox" />
</div>
<div id="alert"></div>
<script>
function checkValidInput() {
$(".validateYearTextBox").keydown(function(event) {
if (!((event.keyCode == 46 ||
event.keyCode == 8 ||
event.keyCode == 37 ||
event.keyCode == 39 ||
event.keyCode == 9) ||
$(this).val().length < 4 &&
((event.keyCode >= 48 && event.keyCode <= 57) ||
(event.keyCode >= 96 && event.keyCode <= 105)))) {
// Stop the event
event.preventDefault();
return false;
}
// count number of characters entered
var cs = $('.validateYearTextBox').val().length;
if(cs == 3)
{
$('#alert').html('valid');
}
else
{
$('#alert').html('');
}
});
}
$(document).ready(function() {
checkValidInput();
});
</script>
Upvotes: 2
Reputation: 3192
I would do something like this.
function checkValidInput() {
$(".validateYearTextBox").keydown(function(event) {
if( $(this).val().length == 3){
$('#alert').html('<p>SUCCESS</p>');
}
if (!((event.keyCode == 46 ||
event.keyCode == 8 ||
event.keyCode == 37 ||
event.keyCode == 39 ||
event.keyCode == 9) ||
$(this).val().length < 4 &&
((event.keyCode >= 48 && event.keyCode <= 57) ||
(event.keyCode >= 96 && event.keyCode <= 105)))) {
// Stop the event
event.preventDefault();
return false;
}
});
}
$(document).ready(function() {
checkValidInput();
});
Upvotes: 0
Reputation: 74738
You can use regular expression for it and change to keyup
event:
function checkValidInput() {
var re = /\d{4}/g,
dt = $('.validateYearTextBox'),
msg;
msg = re.test(dt.val()) ? "Valid" : "Invalid";
$('#alert').text(msg);
}
$(".validateYearTextBox").keyup(checkValidInput);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="main" role="main">
Input a 4-digit:
<input type="text" class="validateYearTextBox" />
</div>
<div id="alert"></div>
Upvotes: 0
Reputation: 5049
Try this:
Jsfiddle: https://jsfiddle.net/jz1ra36d/
just add:
$(".validateYearTextBox").keyup(function(event) {
if( $(this).val().length == 4){
$("#alert").text("valid")
} else {
$("#alert").text("")
}
});
Upvotes: 3