CODEWITHSUNDEEP
javascriptc#ajaxasp.net-mvc-4
rakshith
rakshith

Reputation: 784

how to return the multiple lists from controller action to ajax success call back function

I am creating a mvc .net project in which i have the jquery ajax request is as follows

$.ajax({
        url: "@Url.Action("getdata", "SeatPlans")",
        data: { seat_plane_id : 17},
    type: "POST",
    dataType: "json",
    success: function (data) {
        loadData(data);
    },
    error: function () {
        alert("Failed! Please try again.");
    }
});

which call the following controller action

public JsonResult getdata(int seat_plane_id)
    {
        int lid = seat_plane_id;
        List<SeatPlans> allUser = new List<SeatPlans>();
        allUser = db.SEATPLAN.Where(d => d.layout_id == lid).ToList();
        lid++;
        List<SeatPlans> allUser1 = new List<SeatPlans>();
        allUser1 = db.SEATPLAN.Where(d => d.layout_id == lid).ToList();

        return new JsonResult { Data = allUser,JsonRequestBehavior = JsonRequestBehavior.AllowGet };
    }

the code is working fine. the controller action send the data in allUser to callback function.

but what i need is that i want to send both data in alluser and allUser1 to the success function of ajax call

Upvotes: 7

Views: 3878

Answers (3)

Kathleen Turner
Kathleen Turner

Reputation: 26

I would create a class that has 2 properties

int lid = seat_plane_id;
List<List<SeatPlans>> listOfSeatPlans (a collection of collections)

List<List<SeatPlans>> list = new ...
list.Add(allUser);
list.Add(someUsers);

Now you can return the class object back to JSON

Upvotes: 1

Codrin Faca
Codrin Faca

Reputation: 85

I imagine you want to keep the lists separated. Wrap them in an object.

var data = new { allUser = allUser , allUser1 = allUser1 }; 
return Json(yourObject, JsonRequestBehavior.AllowGet);

You can access them in your JS like this:

success: function (data) {
   var allUser = data[0];
   var allUser1 = data[1];
   //use the data as you see fit.
   loadData(allUser);
   loadData(allUser1 );
},

Upvotes: 7

diiN__________
diiN__________

Reputation: 7656

You just have to modify your Where clause so you don't need two different lists for the users. Try this in your getdata method:

public JsonResult getdata(int seat_plane_id)
{
    int lid = seat_plane_id;
    List<SeatPlans> allUser = new List<SeatPlans>();
    allUser = db.SEATPLAN.Where(d => d.layout_id == lid || d.layout_id == (lid+1)).ToList();

    return new JsonResult { Data = allUser,JsonRequestBehavior = JsonRequestBehavior.AllowGet };
}

allUser now includes all the desired data.

Upvotes: 3

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