Reputation: 129
I'm trying to create a form with the following behavior:
I'm currently stuck with step 2. The code for hyperlink insertion window is this one:
Private Sub PSIC_Click()
Me.[PSIC].SetFocus
On Error GoTo browse_stop
RunCommand acCmdInsertHyperlink
browse_stop:
End Sub
When I try to apply different if then variations it doesn't work as expected. Either I fail in properly applying if then or in determining that the form is empty.
Upvotes: 1
Views: 112
Reputation: 1714
The OnClick()
event of your hyperlink textbox would be:
Private Sub PSIC_Click()
On Error GoTo browse_stop
If ISNULL(Me!PSIC) Then
RunCommand acCmdInsertHyperlink
End If
browse_stop:
End Sub
I removed SetFocus
because clicking on the textbox should automatically set the focus, but if you need it there for some other reason it wasn't really hurting anything.
The "Clear form" command button's OnClick()
event would be:
Private Sub cmdClearForm_Click()
Me!PSIC = NULL
End Sub
Upvotes: 2
Reputation: 3
To open a hyperlink from a form in MS Access:
In Design View make sure that the hyperlink is in its own text box and then go to the 'property sheet' then half way down you should see the option for Hyperlink Address. In here add the address of the hyperlink.
If you want to click on an image and have it open a hyperlink then right-click on the image go to hyperlink.
Upvotes: 0